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  • E.XKC's basketball team(The Preliminary Contest for ICPC Asia Xuzhou 2019)

    https://nanti.jisuanke.com/t/41387

    解:

    离散化+线段树。

      1 #define IOS ios_base::sync_with_stdio(0); cin.tie(0);
      2 #include <cstdio>//sprintf islower isupper
      3 #include <cstdlib>//malloc  exit strcat itoa system("cls")
      4 #include <iostream>//pair
      5 #include <fstream>//freopen("C:\Users\13606\Desktop\草稿.txt","r",stdin);
      6 #include <bitset>
      7 #include <map>
      8 //#include<unordered_map>
      9 #include <vector>
     10 #include <stack>
     11 #include <set>
     12 #include <string.h>//strstr substr
     13 #include <string>
     14 #include <time.h>//srand(((unsigned)time(NULL))); Seed n=rand()%10 - 0~9;
     15 #include <cmath>
     16 #include <deque>
     17 #include <queue>//priority_queue<int, vector<int>, greater<int> > q;//less
     18 #include <vector>//emplace_back
     19 //#include <math.h>
     20 //#include <windows.h>//reverse(a,a+len);// ~ ! ~ ! floor
     21 #include <algorithm>//sort + unique : sz=unique(b+1,b+n+1)-(b+1);+nth_element(first, nth, last, compare)
     22 using namespace std;//next_permutation(a+1,a+1+n);//prev_permutation
     23 #define fo(a,b,c) for(register int a=b;a<=c;++a)
     24 #define fr(a,b,c) for(register int a=b;a>=c;--a)
     25 #define mem(a,b) memset(a,b,sizeof(a))
     26 #define pr printf
     27 #define sc scanf
     28 #define ls rt<<1
     29 #define rs rt<<1|1
     30 typedef long long ll;
     31 void swapp(int &a,int &b);
     32 double fabss(double a);
     33 int maxx(int a,int b);
     34 int minn(int a,int b);
     35 int Del_bit_1(int n);
     36 int lowbit(int n);
     37 int abss(int a);
     38 //const long long INF=(1LL<<60);
     39 const double E=2.718281828;
     40 const double PI=acos(-1.0);
     41 const int inf=(1<<30);
     42 const double ESP=1e-9;
     43 const int mod=(int)1e9+7;
     44 const int N=(int)1e6+10;
     45 
     46 int Max[N<<2];
     47 int ans[N];
     48 ll a[N],ta[N],tb[N];
     49 int LS(int n)
     50 {
     51     int m=0;
     52     for(int i=1;i<=n;++i)
     53         tb[++m]=ta[i];
     54     sort(tb+1,tb+1+m);
     55     m=unique(tb+1,tb+1+m)-tb-1;
     56     for(int i=1;i<=n;++i)
     57         ta[i]=lower_bound(tb+1,tb+1+m,ta[i])-tb;
     58     return m;
     59 }
     60 void up(int rt)
     61 {
     62     Max[rt]=max(Max[rt<<1],Max[rt<<1|1]);
     63 }
     64 
     65 void update_dot(int pos,int V,int l,int r,int rt)
     66 {
     67     if(l==r)
     68     {
     69         Max[rt]=max(Max[rt],V);
     70         return;
     71     }
     72 
     73     int mid=(l+r)>>1;
     74     if(pos<=mid)
     75         update_dot(pos,V,l,mid,rt<<1);
     76     else
     77         update_dot(pos,V,mid+1,r,rt<<1|1);
     78     up(rt);
     79 }
     80 
     81 int Quert_max(int L,int R,int l,int r,int rt)
     82 {
     83     if(L<=l&&r<=R)
     84         return Max[rt];
     85     int mid=(l+r)>>1;
     86     int ans=0;
     87     if(L<=mid)
     88         ans=max(ans,Quert_max(L,R,l,mid,rt<<1));
     89     if(R>mid)
     90         ans=max(ans,Quert_max(L,R,mid+1,r,rt<<1|1));
     91     return ans;
     92 }
     93 
     94 int main()
     95 {
     96     int n;
     97     ll m;
     98     sc("%d%lld",&n,&m);
     99     for(int i=1;i<=n;++i)
    100         sc("%lld",&a[i]),ta[i]=a[i],ta[i+n]=a[i]+m;
    101     LS(2*n);
    102     ans[n]=-1;
    103     update_dot(ta[n],n,1,2*n,1);
    104     for(int i=n-1;i>=1;--i)
    105     {
    106         int temp=Quert_max(ta[i+n],2*n,1,2*n,1);
    107         int pos=temp;
    108         if(pos<i)
    109             ans[i]=-1;
    110         else
    111             ans[i]=pos-i+1-2;
    112         update_dot(ta[i],i,1,2*n,1);
    113     }
    114     for(int i=1;i<=n;++i)
    115         pr("%d%c",ans[i],i==n?'
    ':' ');
    116     return 0;
    117 }
    118 
    119 /**************************************************************************************/
    120 
    121 int maxx(int a,int b)
    122 {
    123     return a>b?a:b;
    124 }
    125 
    126 void swapp(int &a,int &b)
    127 {
    128     a^=b^=a^=b;
    129 }
    130 
    131 int lowbit(int n)
    132 {
    133     return n&(-n);
    134 }
    135 
    136 int Del_bit_1(int n)
    137 {
    138     return n&(n-1);
    139 }
    140 
    141 int abss(int a)
    142 {
    143     return a>0?a:-a;
    144 }
    145 
    146 double fabss(double a)
    147 {
    148     return a>0?a:-a;
    149 }
    150 
    151 int minn(int a,int b)
    152 {
    153     return a<b?a:b;
    154 }
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  • 原文地址:https://www.cnblogs.com/--HPY-7m/p/11482403.html
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