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  • 类型识别

     

     C++中如何得到动态类型?

    #include <iostream>
    #include <string>
    
    using namespace std;
    
    class Base
    {
    public:
        virtual string type()
        {
            return "Base";
        }
    };
    
    class Derived : public Base
    {
    public:
        string type()
        {
            return "Derived";
        }
        
        void printf()
        {
            cout << "I'm a Derived." << endl;
        }
    };
    
    class Child : public Base
    {
    public:
        string type()
        {
            return "Child";
        }
    };
    
    void test(Base* b)
    {
        /* 危险的转换方式 */
        // Derived* d = static_cast<Derived*>(b);
        
        if( b->type() == "Derived" )
        {
            Derived* d = static_cast<Derived*>(b);
            
            d->printf();
        }
        
        // cout << dynamic_cast<Derived*>(b) << endl;
    }
    
    
    int main(int argc, char *argv[])
    {
        Base b;
        Derived d;
        Child c;
        
        test(&b);
        test(&d);
        test(&c);
        
        return 0;
    }

     

     

    #include <iostream>
    #include <string>
    #include <typeinfo>
    
    using namespace std;
    
    class Base
    {
    public:
        virtual ~Base()
        {
        }
    };
    
    class Derived : public Base
    {
    public:
        void printf()
        {
            cout << "I'm a Derived." << endl;
        }
    };
    
    void test(Base* b)
    {
        const type_info& tb = typeid(*b);
        
        cout << tb.name() << endl;
    }
    
    int main(int argc, char *argv[])
    {
        int i = 0;
        
        const type_info& tiv = typeid(i);
        const type_info& tii = typeid(int);
        
        cout << (tiv == tii) << endl;
        
        Base b;
        Derived d;
        
        test(&b);
        test(&d);
        
        return 0;
    }

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  • 原文地址:https://www.cnblogs.com/-glb/p/12025345.html
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