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  • LeetCode OJ:Candy(糖果问题)

    There are N children standing in a line. Each child is assigned a rating value.

    You are giving candies to these children subjected to the following requirements:

    • Each child must have at least one candy.
    • Children with a higher rating get more candies than their neighbors.

    What is the minimum candies you must give?

    一个抠门的人要给一群孩子发糖果,在保证在相邻的孩子之间的rating较高者应该比rating低的获得更多的糖果的情况下,怎样发最少的糖果。

    左右各遍历一次即可,代码如下所示:

     1 class Solution {
     2 public:
     3     int candy(vector<int>& ratings) {
     4         int sz = ratings.size();
     5         vector<int>candy(sz, 0);
     6         if(sz == 0) return 0;
     7         if(sz == 1) return 1;
     8         candy[0] = 1;
     9         for(int i = 1; i < sz; ++i){
    10             if(ratings[i] > ratings[i-1])
    11                 candy[i] = candy[i-1] + 1;
    12             else
    13                 candy[i] = 1;
    14         }
    15         for(int i = sz-2; i >= 0; i--){
    16             if(ratings[i] > ratings[i+1])
    17                 if(candy[i] <= candy[i+1])
    18                     candy[i] = candy[i+1] + 1;
    19         }
    20         int sum = accumulate(candy.begin(), candy.end(), 0);
    21         return sum;
    22     }
    23 };
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  • 原文地址:https://www.cnblogs.com/-wang-cheng/p/5002861.html
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