zoukankan      html  css  js  c++  java
  • The Fifth Season Gym

    Cersei and Jaime has stolen n gold coins from the Casterly Rock reserves. They decided to play a game while the disappearence is not detected.

    The game consists of q rounds. At the beginning of each round all n coins lie in a heap. The players move in rotation, taking from the heap no less than ki and no more than li coins (ki ≤ lii is the number of round). The player who can't do the move loses.

    Cersei and Jaime have determined the pairs of numbers (ki, li) for each round of the game. They don't see any point in finding out who wins in what round as they choose who moves the first by flipping a coin. They are interested in the maximal length of each round, provided that they play optimally (intend to win). The length of the round is the total number of moves made by both Cersei and Jaime.

    Your task is to find the maximal possible length of each round of the game.

    Input

    The first line contains two integers n and q — the number of coins and the number of rounds (1 ≤ n ≤ 106, 1 ≤ q ≤ 105).

    Each of the next q lines contains two integers ki and li   — the minimal and maximal number of coins that could be taken at one turn in the i-th round.

    Output

    Write q space-separated integers. The i-th number should be equal to the maximal possible length of the i-th round.

    Examples

    Input
    10 2
    1 1
    5 6
    Output
    10 1 


     1 #include <stdio.h>
     2 #include <string.h>
     3 
     4 int main()
     5 {
     6     int n, q, a, b;
     7     scanf("%d %d", &n, &q);
     8     while(q--)
     9     {
    10         scanf("%d %d", &a, &b);
    11 
    12         if(n%(a+b)<a) printf("%d", n/(a+b)*2);
    13         else printf("%d", n/(a+b)*2+1);
    14 
    15         if(q>0) printf(" ");
    16         else printf("
    ");
    17     }
    18     return 0;
    19 }
  • 相关阅读:
    项目经验分享(上)
    socket.io实现在线群聊
    socket.io中文文档
    常用的Sublime Text插件及安装方法
    常用的Atom插件
    atom及其插件activate-power-mode下载安装
    jeesite快速开发平台
    js权威指南
    hexSHA1散列加密解密(不可逆)
    腾讯云企业邮箱
  • 原文地址:https://www.cnblogs.com/0xiaoyu/p/11671452.html
Copyright © 2011-2022 走看看