zoukankan      html  css  js  c++  java
  • pat1008

    The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.

    For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.

    Input Specification:

    Each input file contains one test case. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100.

    Output Specification:

    For each test case, print the total time on a single line.

    Sample Input:

    3 2 3 1
    

    Sample Output:

    41
    模拟。。先到2楼再到3楼再到1楼
    #include<iostream>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    int a[105];
    int main()
    {
        int n;
        while(cin>>n)
        {
            memset(a,0,sizeof(a));
            a[0]=0;
            int ans=5*n;
            for(int i=1;i<=n;i++)
            {
                cin>>a[i];
            }
            for(int i=1;i<=n;i++)
            {
                if(a[i]>a[i-1])
                    ans+=6*(a[i]-a[i-1]);
                else if(a[i]<a[i-1])
                    ans+=4*(a[i-1]-a[i]);
            }
            cout<<ans<<endl;
        }
        return 0;
    }

    提交代码

  • 相关阅读:
    函数式语言(老师作业)
    session/cookie
    Linux根目录下各个目录的功能介绍
    Navicat12安装文件和破解补丁
    正则表达式验证示例
    RequestDispatcher接口示例
    hello2部分源码解析
    Introduction of Servlet Filter
    关于hello1中的web.xml解析
    Annotation解释
  • 原文地址:https://www.cnblogs.com/2014slx/p/7800159.html
Copyright © 2011-2022 走看看