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  • Self Numbers C语言 UVA640

    In 1949 the Indian mathematician D.R. Kaprekar discovered a class of numbers called self-numbers. For any positive integer n, define d(n) to be n plus the sum of the digits of n. (The d stands for digitadition, a term coined by Kaprekar.) For example, d(75) = 75 + 7 + 5 = 87. Given any positive integer n as a starting point, you can construct the infinite increasing sequence of integers n, d(n), d(d(n)), d(d(d(n))), .... For example, if you start with 33, the next number is 33 + 3 + 3 = 39, the next is 39 + 3 + 9 = 51, the next is 51 + 5 + 1 = 57, and so you generate the sequence

    33, 39, 51, 57, 69, 84, 96, 111, 114, 120, 123, 129, 141, ...

    The number n is called a generator of d(n). In the sequence above, 33 is a generator of 39, 39 is a generator of 51, 51 is a generator of 57, and so on. Some numbers have more than one generator: for example, 101 has two generators, 91 and 100. A number with no generators is a self-number. There are thirteen self-numbers less than 100: 1, 3, 5, 7, 9, 20, 31, 42, 53, 64, 75, 86, and 97.

    Write a program to output all positive self-numbers less than or equal 1000000 in increasing order, one per line.


    Sample Output

    1
    3
    5
    7
    9
    20
    31
    42
    53
    64
    |
    | <-- a lot more numbers
    |
    9903
    9914
    9925
    9927
    9938
    9949
    9960
    9971
    9982
    9993
    |
    |
    |

    用离线计算的方法,计算出1000000以内的所有非自我数,将这些数筛掉后再从小到大按序输出。

     1 //UVA 640
     2 #include <stdio.h>
     3 
     4 int a[1000001]; 
     5 
     6 int main(void){
     7     int i,b,c;
     8     for(i=0;i<=1000000;++i){
     9         b=i;c=i;
    10         while(c){
    11             b+=c%10;
    12             c/=10;
    13         }
    14         a[b]=1;    
    15     }
    16     for(i=1;i<=1000000;++i)
    17         if (!a[i]) printf("%d
    ",i);
    18     return 0;
    19 }
    View Code
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  • 原文地址:https://www.cnblogs.com/20174317zhuyuan/p/9396312.html
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