习题6-4 使用函数输出指定范围内的Fibonacci数

#include<stdio.h>

int fib(int n);
void PrintFN(int m, int n);
int main(void)
{
    int m, n, t;

    scanf_s("%d %d %d", &m, &n, &t);
    printf("fib(%d) = %d
", t, fib(t));
    PrintFN(m, n);

    return 0;
}

int fib(int n)
{
    int a, b, t;
    a = 0;
    b = 1;
    /*
        斐波拉契数列
    */
    for (int i = 2; i <= n; i++)
    {
        t = a + b;
        a = b;
        b = t;
    }

    return b;
}
void PrintFN(int m, int n)
{
    int i = 1;
    int count = 0;            //对符合条件的斐波拉契数进行统计
    while (fib(i) <= n)
    {
        if (fib(i) >= m)
        {
            count++;
            if (count == 1)
            {
                printf("%d", fib(i));
            }
            else
            {
                printf(" %d", fib(i));
            }
        }
        i++;
    }
    if (count == 0)
    {
        printf("No Fibonacci number
");
    }
}