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  • 习题6-5 使用函数验证哥德巴赫猜想

     1 #include<stdio.h>
     2 #include<math.h>
     3 
     4 int prime(int p);
     5 void Goldbach(int n);
     6 
     7 int main()
     8 {
     9     int m, n, i, cnt;
    10 
    11     scanf_s("%d %d", &m, &n);
    12     if (prime(m) != 0)
    13     {
    14         printf("%d is a prime number
    ", m);
    15     }
    16     if (m < 6)
    17     {
    18         m = 6;
    19     }
    20     if (m % 2)
    21     {
    22         m++;
    23     }
    24     cnt = 0;
    25     for (i = m; i <= n; i += 2)
    26     {
    27         Goldbach(i);
    28         cnt++;
    29         if (cnt % 5)
    30         {
    31             printf(", ");
    32         }
    33         else
    34         {
    35             printf("
    ");
    36         }
    37     }
    38     return 0;
    39 }
    40 int prime(int p) 
    41 {
    42     int ret;
    43     if (p <= 1)
    44     {
    45         ret = 0;
    46     }
    47     else
    48     {
    49         ret = 1;
    50         for (int i = 2; i < p; i++)
    51         {
    52             if (p % i == 0)
    53             {
    54                 ret = 0;
    55                 break;
    56             }
    57         }
    58     }
    59 
    60     return ret;
    61 }
    62 void Goldbach(int n)
    63 {
    64     for (int i = 2; i <= n / 2; i++)
    65     {
    66         if (prime(i) * prime(n - i))
    67         {
    68             printf("%d=%d+%d", n, i, n - i);
    69             break;
    70         }
    71     }
    72 }
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  • 原文地址:https://www.cnblogs.com/2018jason/p/10971492.html
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