zoukankan      html  css  js  c++  java
  • 指针例题1

     1 #include <stdio.h>
     2 void minmax(int *a, int len, int *min, int *max);
     3 int main(void)
     4 {
     5     int a[] = {
     6         1,
     7         2,
     8         3,
     9         4,
    10         5,
    11         6,
    12         7,
    13         8,
    14         9,
    15         12,
    16         13,
    17         14,
    18         16,
    19         17,
    20         21,
    21         23,
    22         55,
    23     };
    24     int min, max;
    25     printf("main sizeof(a) = %d
    ", sizeof(a));
    26     printf("main a = %p
    ", a);
    27     minmax(a, sizeof(a) / sizeof(a[0]), &min, &max);
    28     printf("a[0] = %d
    ", a[0]);
    29     printf("min = %d, max = %d
    ", min, max);
    30     int *p = &min;
    31     printf("*p = %d
    ", *p);
    32     printf("p[0] = %d
    ", p[0]);
    33     printf("*a = %d
    ", *a);
    34     return 0;
    35 }
    36 void minmax(int *a, int len, int *min, int *max)
    37 {
    38     printf("minmax sizeof(a) = %d
    ", sizeof(a));
    39     printf("main a = %p
    ", a);
    40     a[0] = 1000;
    41     *min = *max = a[0];
    42     for (int i = 1; i < len; i++)
    43     {
    44         if (a[i] < *min)
    45         {
    46             *min = a[i];
    47         }
    48         if (a[i] > *max)
    49         {
    50             *max = a[i];
    51         }
    52     }
    53 }

  • 相关阅读:
    SVN版本控制器的使用说明(详细过程)
    tomcat服务器的搭建
    git以及gitHub的使用说明书
    gulp的简单使用
    SASS的应用
    springmvc常用注解
    js创建对象的方法
    SVG入门
    http状态码全解
    Ajax参数详解
  • 原文地址:https://www.cnblogs.com/2018jason/p/12054502.html
Copyright © 2011-2022 走看看