1 #include <stdio.h> 2 int leap(int year); //闰年返回1，否则返回0 3 int yeardays(int year, int month, int day); //返回一年中的第几天 4 int days(int year); //返回一年的总天数 5 int main(void) 6 { 7 int birth_year, birth_month, birth_day; 8 int to_year, to_month, to_day; 9 int day_num = 0; 10 scanf("%d %d %d", &birth_year, &birth_month, &birth_day); 11 scanf("%d %d %d", &to_year, &to_month, &to_day); 12 13 if (birth_year == to_year) 14 { 15 day_num = yeardays(to_year, to_month, to_day) - yeardays(birth_year, birth_month, birth_day); 16 } 17 else 18 { 19 day_num = days(birth_year) - yeardays(birth_year, birth_month, birth_day) + 1; 20 for (int i = birth_year + 1; i < to_year; i++) 21 { 22 day_num = day_num + days(i); 23 } 24 day_num = day_num + yeardays(to_year, to_month, to_day); 25 } 26 27 printf("%d ", day_num); 28 29 return 0; 30 } 31 int leap(int year) 32 { 33 int ret; 34 35 if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) 36 { 37 ret = 1; 38 } 39 else 40 { 41 ret = 0; 42 } 43 44 return ret; 45 } 46 int yeardays(int year, int month, int day) 47 { 48 int days = 0; 49 int month_days[2][13] = { 50 {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}, 51 {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}, 52 }; 53 for (int i = 1; i < month; i++) 54 { 55 days = days + month_days[leap(year)][i]; 56 } 57 days = days + day; 58 59 return days; 60 } 61 int days(int year) 62 { 63 int ret; 64 if (leap(year)) 65 { 66 ret = 366; 67 } 68 else 69 { 70 ret = 365; 71 } 72 73 return ret; 74 }
输入两个日期（年 月 日），计算两个日期经过了多少天。
可以输入自己的生日和当前的日期，计算自己来到地球多少天了。
