题目:
Given a set of distinct integers, nums, return all possible subsets.
Note: The solution set must not contain duplicate subsets.
For example,
If nums = [1,2,3]
, a solution is:
[ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ]
题意及分析:给出一个无重复值的集合,要求给出所有可能的子集。这道题直接用动态规划求解,因为每一次backtack的时候都有解,所以在每次backtrack的时候将结果写入即可。
代码:
public class Solution { public List<List<Integer>> subsets(int[] nums) { List<List<Integer>> resList = new ArrayList<>(); Arrays.sort(nums); List<Integer> list=new ArrayList<>(); backtracking(resList, list, nums, 0); // System.out.println(resList); return resList; } public void backtracking(List<List<Integer>> resList,List<Integer> list,int[] nums,int start) { resList.add(new ArrayList<>(list)); for(int i=start;i<nums.length;i++){ list.add(nums[i]); backtracking(resList, list, nums, i+1); list.remove(list.size()-1); } } }