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  • hdu 1001 Sum Problem

    Sum Problem

    Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 487269    Accepted Submission(s): 123725


    Problem Description
    Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

    In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
     
    Input
    The input will consist of a series of integers n, one integer per line.
     
    Output
    For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
     
    Sample Input
    1 100
     
    Sample Output
    1 5050
     
     
    水题不加题解   可以直接看明白的
     1 #include<stdio.h>
     2 #include<cmath>
     3 #include<iostream>
     4 #include<cstring>
     5 #include<algorithm>
     6 #include<queue>
     7 using namespace std;
     8 int main ()
     9 {
    10     long int n,i,sum;
    11     while(scanf("%ld",&n)!=EOF)
    12     { 
    13      sum=0;
    14      for(i=1;i<=n;i++)
    15      {
    16       sum+=i;
    17      }
    18      printf("%ld
    ",sum);
    19      printf("
    ");
    20     }
    21 return 0;
    22 }
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  • 原文地址:https://www.cnblogs.com/52why/p/7478027.html
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