1060 Are They Equal (25分)

If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0 with simple chopping. Now given the number of significant digits on a machine and two float numbers, you are supposed to tell if they are treated equal in that machine.

Input Specification:

Each input file contains one test case which gives three numbers N, A and B, where N (<) is the number of significant digits, and A and B are the two float numbers to be compared. Each float number is non-negative, no greater than 1, and that its total digit number is less than 100.

Output Specification:

For each test case, print in a line YES if the two numbers are treated equal, and then the number in the standard form 0.d[1]...d[N]*10^k (d[1]>0 unless the number is 0); or NO if they are not treated equal, and then the two numbers in their standard form. All the terms must be separated by a space, with no extra space at the end of a line.

Note: Simple chopping is assumed without rounding.

Sample Input 1:

3 12300 12358.9

Sample Output 1:

YES 0.123*10^5

Sample Input 2:

3 120 128

Sample Output 2:

NO 0.120*10^3 0.128*10^3

未全过代码

#define _CRT_SECURE_NO_WARNINGS
#include <climits>
#include<iostream>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<algorithm>
#include<string>
#include<cmath>
using namespace std;

int main()
{
    int N;
    float num1, num2;
    int p1, p2,n1,n2;
    p1 = p2 = 0;
    n1 = n2 = 0;
    cin >> N >> num1 >> num2;
    stack<int>S1, S2;
    while (num1 - floor(num1) != 0.0)
    {
        num1 *= 10.0;
        p1++;
    }
    while (num2 - floor(num2) != 0.0)
    {
        num2 *= 10.0;
        p2++;
    }
    int N1 = static_cast<int>(num1);
    int N2 = static_cast<int>(num2);
    while (N1)
    {
        S1.push(N1 % 10);
        N1 /= 10;
        n1++;
    }
    while (N2)
    {
        S2.push(N2 % 10);
        N2 /= 10;
        n2++;
    }
    n1 -= p1;
    n2 -= p2;
    int ans1 = 0, ans2 = 0;
    int s1 = 0, s2 = 0;
    for (int i = 0; i < N; i++)
    {
        if (!S1.empty()) {
            ans1 = ans1 * 10 + S1.top();
            S1.pop();
            s1++;
        }
        if (!S2.empty()) {
            ans2 = ans2 * 10 + S2.top();
            S2.pop();
            s2++;
        }
    }
    if (s1 != N) {
        ans1 *= 10;
        s1++;
    }
    if (s2 != N) {
        ans2 *=10;
        s2++;
    }
    if (ans1 == ans2 && n1 == n2)
    {
        if(ans1==0)
            cout << "YES "<< ans1;
        else
        {
            cout << "YES" << " 0." << ans1;
            if (n1 > 0)
                cout << "*10^" << n1;
        }
    }
    else
    {
        cout << "NO ";
        cout << "0." << ans1;
        if (n1 > 0)
            cout << "*10^" << n1<<" ";
        cout << "0." << ans2;
        if (n2 > 0)
            cout << "*10^" << n1;
    }
}