ef leap_year(year):
return (year//4==0 and year//100!=0) or (year //400==0)
def which_day(year,month,day):
total=0
days_of_month=[31,28,31,30,31,30,31,31,30,31,30,31]
for index in range (month-1):
total += days_of_month[index]
if month >2 and leap_year(year):
total += 1
return total + day
if __name__ == '__main__':
print(which_day(1980,11,28))
结果: 332