zoukankan      html  css  js  c++  java
  • Vitya in the Countryside

    Every summer Vitya comes to visit his grandmother in the countryside. This summer, he got a huge wart. Every grandma knows that one should treat warts when the moon goes down. Thus, Vitya has to catch the moment when the moon is down.

    Moon cycle lasts 30 days. The size of the visible part of the moon (in Vitya's units) for each day is 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, and then cycle repeats, thus after the second 1 again goes 0.

    As there is no internet in the countryside, Vitya has been watching the moon for nconsecutive days and for each of these days he wrote down the size of the visible part of the moon. Help him find out whether the moon will be up or down next day, or this cannot be determined by the data he has.

    Input

    The first line of the input contains a single integer n (1 ≤ n ≤ 92) — the number of consecutive days Vitya was watching the size of the visible part of the moon.

    The second line contains n integers ai (0 ≤ ai ≤ 15) — Vitya's records.

    It's guaranteed that the input data is consistent.

    Output

    If Vitya can be sure that the size of visible part of the moon on day n + 1 will be less than the size of the visible part on day n, then print "DOWN" at the only line of the output. If he might be sure that the size of the visible part will increase, then print "UP". If it's impossible to determine what exactly will happen with the moon, print -1.

    Example

    Input
    5
    3 4 5 6 7
    Output
    UP
    Input
    7
    12 13 14 15 14 13 12
    Output
    DOWN
    Input
    1
    8
    Output
    -1

    Note

    In the first sample, the size of the moon on the next day will be equal to 8, thus the answer is "UP".

    In the second sample, the size of the moon on the next day will be 11, thus the answer is "DOWN".

    In the third sample, there is no way to determine whether the size of the moon on the next day will be 7 or 9, thus the answer is -1.

    就是给出一个数列,按照给的三十天样例,看看能不能确定下一天是down还是up

    注意0和15这两个中转点。

    代码:

    #include<bits/stdc++.h>
    using namespace std;
    
    int main()
    {
        int n,a[100];
        int flag;
        cin>>n;
        for(int i = 0; i < n;i ++)
        {
            cin>>a[i];
            if(i && a[i] > a[i - 1])flag = 1;
            else if(i && a[i] < a[i - 1])flag = -1;
            else if(a[i] == 15)flag = 1;
            else if(a[i] == 0)flag = -1;
            else flag = 0;
        }
        if(flag > 0)
        {
            if(a[n - 1] == 15)cout<<"DOWN";
            else cout<<"UP";
        }
        else if(flag < 0)
        {
            if(a[n - 1] == 0)cout<<"UP";
            else cout<<"DOWN";
        }
        else cout<<-1;
    }
  • 相关阅读:
    安卓AndroidManifest.xml介绍
    Android系统开发入门
    蓝牙协议(bluetooth spec)
    解决:NoSuchAlgorithmException: Algorithm HmacSHA1 not available
    Spring bean 实现初始化、销毁方法的方式及顺序
    解决: maven编译项目报“非法字符: 65279 ”错误
    解决:eclipse 非正常关闭,导致无法正常启动
    ffmpeg 音频转换: use ffmpeg convert the audio from stereo to mono without changing the video part
    win10家庭版快速升级专业版
    Linux下更改目录及其下的子目录和文件的访问权限
  • 原文地址:https://www.cnblogs.com/8023spz/p/7668572.html
Copyright © 2011-2022 走看看