zoukankan      html  css  js  c++  java
  • The Triangle

    7
    3 8
    8 1 0
    2 7 4 4
    4 5 2 6 5

    (Figure 1)
    Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right.
    Input
    Your program is to read from standard input. The first line contains one integer N: the number of rows in the triangle. The following N lines describe the data of the triangle. The number of rows in the triangle is > 1 but <= 100. The numbers in the triangle, all integers, are between 0 and 99.
    Output
    Your program is to write to standard output. The highest sum is written as an integer.
    Sample Input
    5
    7
    3 8
    8 1 0 
    2 7 4 4
    4 5 2 6 5
    Sample Output
    30

    简单动态规划从下往上相邻找最大加上去。像二叉树。

    代码:

    #include <iostream>
    #include <map>
    #include <queue>
    #include <cmath>
    #include <cstdio>
    #include <algorithm>
    #include <cstring>
    #define inf 10001
    using namespace std;
    int main()
    {
    
        int n,d,sum = 0;
        int a[100][100] = {0};
        cin>>n;
        for(int i = 0;i < n;i ++)
        {
            for(int j = 0;j <= i;j ++)
            {
                cin>>a[i][j];
            }
        }
        for(int i = n - 2;i >= 0;i --)
        {
            for(int j = 0;j <= i;j ++)
                a[i][j] += max(a[i+1][j],a[i+1][j+1]);
        }
        cout<<a[0][0];
    }
  • 相关阅读:
    DFS+输出路线--poj2488--A Knight's Journey
    三:矩阵快速幂应用
    二:矩阵快速幂
    一:快速求幂
    动态规划空间复杂度的优化--滚动数组
    暴力--全排列+排列组合+组合(求子集)
    next_permutation 与 prev_permutation(全排列算法)
    BFS入门--POJ3278--抓羊
    java基础编程题
    计蒜客
  • 原文地址:https://www.cnblogs.com/8023spz/p/7868932.html
Copyright © 2011-2022 走看看