1082. Read Number in Chinese (25)

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu". Note: zero ("ling") must be handled correctly according to the Chinese tradition. For example, 100800 is "yi Shi Wan ling ba Bai".

Input Specification:

Each input file contains one test case, which gives an integer with no more than 9 digits.

Output Specification:

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

Sample Input 1:

-123456789

Sample Output 1:

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

Sample Input 2:

100800

Sample Output 2:

yi Shi Wan ling ba Bai


如果是100000005，应该读yi Yi ling wu,注意wan的输出。暂时想到这么多。
代码：

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
int main()
{
    char num[11];
    scanf("%s",num);
    int n_size = strlen(num);
    char digit[10][5] = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    char unit[9][5] = {"Fu","Shi","Bai","Qian","Wan","Shi","Bai","Qian","Yi"};
    int i = 0,flag = 0,ling = 0;
    if(num[i] == '-')
    {
        flag = 1;
        printf("%s",unit[i ++]);
    }
    while(num[i])
    {
        if(num[i] == '0')
        {
            ling ++;
            if(!i || i != n_size - 1 && num[i + 1] != '0')
            {
                if(!flag)
                {
                    flag = 1;
                }
                else putchar(' ');
                printf("%s",digit[0]);
            }
        }
        else
        {
            if(flag)
            {
                putchar(' ');
            }
            else flag = 1;
            printf("%s",digit[num[i] - '0']);
        }
        if(n_size - i - 1 == 4 && ling != 4)printf(" %s",unit[4]);
        else if(num[i]  != '0' && i != n_size - 1)printf(" %s",unit[n_size - i - 1]);
        i ++;
    }
}