PAT 1042. Shuffling Machine

1042. Shuffling Machine (20)

Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employees collaborate with gamblers by performing inadequate shuffles, many casinos employ automatic shuffling machines. Your task is to simulate a shuffling machine.

The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:

S1, S2, ..., S13, H1, H2, ..., H13, C1, C2, ..., C13, D1, D2, ..., D13, J1, J2

where "S" stands for "Spade", "H" for "Heart", "C" for "Club", "D" for "Diamond", and "J" for "Joker". A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer K (<= 20) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.

Sample Input:

2
36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47

Sample Output:

S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6 H3 D13 J1 J2 C1 C2 C3 C4 D1 S5 H5 H11 H12 C6 C7 C8 C9 S2 S8 S9 H10 D5 D6 D7 H4 H13 C5

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分析

这道题不难，但要注意存在环，所以要创建一个visited数组来遍历

栗子

位置           1      2     3    4      5

牌               S3  H5  C1  D13  J2

交换的顺序  4    2     5     3      1

times=1（即排一遍）

temp储存暂时的信息：

第一步       ！

位置           1      2     3    4      5

牌               S3  H5  C1   S3   J2

交换的顺序  4    2     5     3      1

temp:D13

第二步                             ！

位置           1      2     3    4      5

牌               S3  H5  D13   S3   J2

交换的顺序  4    2     5     3      1

temp:C1

第三步                       ！

位置           1      2     3    4      5

牌               S3  H5  D13   S3  C1

交换的顺序  4    2     5     3      1

temp:J2

第四步                                    ！

位置           1      2     3    4      5

牌               J2   H5  D13   S3  C1

交换的顺序  4    2     5     3      1

temp:J2

第四步        !                        

位置           1      2     3    4      5

牌               J2   H5  D13   S3  C1

交换的顺序  4    2     5     3      1

注意感叹号有回到了1的头上，1-->4-->3-->5-->1是个环，在这里2自己就是个环，2-->2;所以借用visited数组来记录访问过哪些元素

#include<iostream>
#include<vector>
using namespace std;
int main(){
    vector<string> cards={"#","S1","S2","S3","S4","S5","S6","S7","S8","S9","S10","S11","S12","S13",
                          "H1","H2","H3","H4","H5","H6","H7","H8","H9","H10","H11","H12","H13",
                          "C1","C2","C3","C4","C5","C6","C7","C8","C9","C10","C11","C12","C13",
                          "D1","D2","D3","D4","D5","D6","D7","D8","D9","D10","D11","D12","D13","J1","J2"};
    int n;                
    cin>>n;           
    vector<int> order(55);
    for(int i=1;i<=54;i++)
        cin>>order[i];
    for(int i=0;i<n;i++){
        vector<int> visited(55,0);
        for(int j=1;j<=54;j++){
            int tag=j;
            string temp=cards[tag];
            while(visited[tag]==0){
                  visited[tag]=1;
                  string t=temp;
                  temp=cards[order[tag]];
                  cards[order[tag]]=t;
                  tag=order[tag];
            }
        }
    }
    for(int i=1;i<=54;i++)
    i>1?cout<<" "<<cards[i]:cout<<cards[i];
}