zoukankan      html  css  js  c++  java
  • PAT 1050. String Subtraction

    Given two strings S1 and S2, S = S1 - S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1 - S2 for any given strings. However, it might not be that simple to do it fast.

    Input Specification:

    Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 104. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

    Output Specification:

    For each test case, print S1 - S2 in one line.

    Sample Input:

    They are students.
    aeiou
    

    Sample Output:
    Thy r stdnts.

    分析
    这道题对s2遍历一遍,用checked记录s2中出现过的字符,对s1进行遍历输出,如果checked中checked[i]==1,则不输出,否则输出。

    #include<iostream>
    using namespace std;
    int main(){
    	int checked[300]={0};
    	string s1,s2;
    	getline(cin,s1);
    	getline(cin,s2);
    	for(int i=0;i<s2.size();i++)
    		checked[s2[i]]=1;
    	for(int i=0;i<s1.size();i++)
    	    if(checked[s1[i]]==1)
    	       continue;
    	    else 
    	       cout<<s1[i];
    	return 0;
    }
    
  • 相关阅读:
    LWIP的底层结构(物理层)
    Source insight 支持汇编
    Camera Vision
    i2c-tools的使用方法及举例
    浅析C语言中strtol()函数与strtoul()函数的用法
    CF540C Ice Cave
    CF540B School Marks
    hdu5122 K.Bro Sorting
    hdu1013 Digital Roots
    蓝桥杯 算法提高 递推求值
  • 原文地址:https://www.cnblogs.com/A-Little-Nut/p/8330711.html
Copyright © 2011-2022 走看看