PAT 1124 Raffle for Weibo Followers

John got a full mark on PAT. He was so happy that he decided to hold a raffle（抽奖） for his followers on Weibo -- that is, he would select winners from every N followers who forwarded his post, and give away gifts. Now you are supposed to help him generate the list of winners.

Input Specification:

Each input file contains one test case. For each case, the first line gives three positive integers M (≤ 1000), N and S, being the total number of forwards, the skip number of winners, and the index of the first winner (the indices start from 1). Then M lines follow, each gives the nickname (a nonempty string of no more than 20 characters, with no white space or return) of a follower who has forwarded John's post.

Note: it is possible that someone would forward more than once, but no one can win more than once. Hence if the current candidate of a winner has won before, we must skip him/her and consider the next one.

Output Specification:

For each case, print the list of winners in the same order as in the input, each nickname occupies a line. If there is no winner yet, print Keep going... instead.

Sample Input 1:

9 3 2
Imgonnawin!
PickMe
PickMeMeMeee
LookHere
Imgonnawin!
TryAgainAgain
TryAgainAgain
Imgonnawin!
TryAgainAgain

Sample Output 1:

PickMe
Imgonnawin!
TryAgainAgain

Sample Input 2:

2 3 5
Imgonnawin!
PickMe

Sample Output 2:

Keep going...

#include<iostream>//水题
#include<map>
using namespace std;
int main(){
  int m, n, s, cnt=0;
  cin>>m>>n>>s;
  string r;
  map<string, int> visited;
  for(int i=1; i<=m; i++){
    cin>>r;
    if(i<s) continue;
    else if(i==s){
      cout<<r<<endl;
      visited[r]=1;
    }
    else{
      cnt++;
      if(cnt%n==0){
        if(visited[r]==0){
          cout<<r<<endl;
          visited[r]=1;
          cnt=0;
        }else
          cnt--;
      }
    }
  }
  if(m<s)
    cout<<"Keep going..."<<endl;
  return 0;
}