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  • Codeforces 1345


    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<cmath>
    #include<map>
    #include<queue>
    #include<vector>
    #include<string>
    #include<fstream>
    using namespace std;
    #define rep(i, a, n) for(int i = a; i <= n; ++ i);
    #define per(i, a, n) for(int i = n; i >= a; -- i);
    typedef long long ll;
    const int N = 3e6 + 105;
    const int mod = 998244353;
    const double Pi = acos(- 1.0);
    const int INF = 0x3f3f3f3f;
    const int G = 3, Gi = 332748118;
    ll qpow(ll a, ll b) { ll res = 1; while(b){ if(b) res = (res * a) % mod; a = (a * a) % mod; b >>= 1;} return res; }
    ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
    //
    ll T, n;
    ll a[N];
    map<ll,int>mp;
     
    int main()
    {
        scanf("%lld",&T);
        ll num = 1e9;
        while(T--){
            scanf("%lld",&n);
            mp.clear();
            for(ll i = 0; i < n; ++ i){
                scanf("%lld",&a[i]);
                //cout<<i<<" "<<(i + a[i] % n + n) % n<<endl;
                mp[(i + a[i] % n + n) % n] ++;
            }
            int flag = 0;
            for(ll i = 0; i < n; ++ i){
                if(!mp[i]||mp[i] > 1) flag = 1;
            }
            if(flag) printf("NO
    ");
            else printf("YES
    ");
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/A-sc/p/12841521.html
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