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  • 【Codeforces 382C】Arithmetic Progression

    【链接】 我是链接,点我呀:)
    【题意】

    让你在n个数字中再加入一个数字 使得这n+1个数字排序之后 相邻两个数字的差都相同

    【题解】

    注意相邻为0的情况 这种情况 只有全都相同才行 只有一种情况 然后就是样例里的a[i]-a[i-1]只有两种数字 然后较小的a[i]-a[i-1]有n-2个,较大的a[i]-a[i-1]有1个,然后较大的是较小的两倍 注意这些细节就好了

    【代码】

    import java.io.*;
    import java.util.*;
    
    public class Main {
        
        
        static InputReader in;
        static PrintWriter out;
            
        public static void main(String[] args) throws IOException{
            //InputStream ins = new FileInputStream("E:\rush.txt");
            InputStream ins = System.in;
            in = new InputReader(ins);
            out = new PrintWriter(System.out);
            //code start from here
            new Task().solve(in, out);
            out.close();
        }
        
        static int N = (int)1e5;
        static class Task{
            
            int n;
            int a[] = new int[N+10];
            HashMap<Integer,Integer> dic = new HashMap<>();
            
            public void solve(InputReader in,PrintWriter out) {
            	n = in.nextInt();
            	for (int i = 1;i <= n;i++) a[i] = in.nextInt();
            	Arrays.sort(a, 1,n+1);
            	if (n==1) {
            		out.println(-1);
            	}else if (n==2) {
            		if (a[1]==a[2]) {
            			out.println(1);
            			out.println(a[1]);
            		}else {
            			if ( (a[1]+a[2])%2==0) {
            				int temp = a[2]-a[1];
            				out.println(3);
            				out.print((a[1]-temp)+" "+((a[1]+a[2])/2)+" "+(a[2]+temp) );
            			}else {
            				int temp = a[2]-a[1];
            				out.println(2);
            				out.println((a[1]-temp)+" "+(a[2]+temp));
            			}
            		}
            	}else {
            		int temp = a[2]-a[1];
            		boolean ok = true;
            		for (int i = 3;i <= n;i++) {
            			if (a[i]-a[i-1]!=temp) {
            				ok = false;
            			}
            		}
            		if (ok) {
            			if (temp==0) {
            				out.println(1);
            				out.println(a[1]);
            			}else {
            				out.println(2);
            				out.println((a[1]-temp)+" "+(a[n]+temp));
            			}
            		}else {
            			 for (int i = 2;i <= n;i++) {
            				 if (dic.containsKey(a[i]-a[i-1])) {
            					 int x = dic.get(a[i]-a[i-1]);
            					 dic.put(a[i]-a[i-1],x+1);
            				 }else {
            					 dic.put(a[i]-a[i-1], 1);
            				 }
            			 }
            			 if (dic.size()>2) {
            				 out.println(0);
            			 }else {
            				 Iterator it = dic.keySet().iterator();
            				 int temp1 = (int)it.next();
            				 int temp2 = (int)it.next();
            				 if (temp1>temp2) {
            					 int xx = temp1;temp1 = temp2;temp2 = xx;
            				 }
            				 if ( (temp2 == temp1*2) && ( (int)dic.get(temp2) )==1 ) {
            					 out.println(1);
            					 for (int i = 2;i <= n;i++) {
            						 if (a[i]-a[i-1]==temp2) {
            							 out.println(a[i-1]+temp1);
            						 }
            					 }
            				 }else {
            					 out.println(0);
            				 }
            			 }
            		}
            	}
            }
        }
    
        
    
        static class InputReader{
            public BufferedReader br;
            public StringTokenizer tokenizer;
            
            public InputReader(InputStream ins) {
                br = new BufferedReader(new InputStreamReader(ins));
                tokenizer = null;
            }
            
            public String next(){
                while (tokenizer==null || !tokenizer.hasMoreTokens()) {
                    try {
                    tokenizer = new StringTokenizer(br.readLine());
                    }catch(IOException e) {
                        throw new RuntimeException(e);
                    }
                }
                return tokenizer.nextToken();
            }
            
            public int nextInt() {
                return Integer.parseInt(next());
            }
        }
    }
    
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  • 原文地址:https://www.cnblogs.com/AWCXV/p/10532561.html
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