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  • 【Codeforces 375A】Divisible by Seven

    【链接】 我是链接,点我呀:)
    【题意】

    让你把一个包含数字1,6,8,9的数字重新组合,使得组合成的数字能被7整除

    【题解】

    我们先提取出来1,6,8,9各1个 然后把剩余的len-4个数字除了0之外放在前面 那么这len-4个除了0之外的数字组成的十进制数字对7的取余结果肯定是0~6之间。 然后我们用这个取余结果,和1,6,8,9的所有全排列一个一个去试,尝试把排列出来的结果放在这len-4个数字的后面 最后发现取余结果为0~6都能找到一个1,6,8,9的排列,使得它放在他们后面,然后取余结果为0 最后把剩余的0放在1,6,8,9的后面就好。

    【代码】

    import java.io.*;
    import java.util.*;
    
    public class Main {
        
        
        static InputReader in;
        static PrintWriter out;
            
        public static void main(String[] args) throws IOException{
            //InputStream ins = new FileInputStream("E:\rush.txt");
            InputStream ins = System.in;
            in = new InputReader(ins);
            out = new PrintWriter(System.out);
            //code start from here
            new Task().solve(in, out);
            out.close();
        }
        
        static int N = 50000;
        static class Task{
            
        	int cnt[] = new int[10];
        	int a[] = {0,1,6,8,9};
        	int b[] = new int[10];
        	boolean bo[] = new boolean[5];
        	int n;
        	String s;
        	int cur = 0;
        	
        	boolean dfs(int dep,int now) {
        		if (dep==5) {
        			int temp = now;
        			for (int i = 1;i <= 4;i++) {
        				temp = temp*10 + b[i];
        				temp = temp%7;
        			}
        			if (temp==0) {
        				for (int i = 1;i <= 4;i++) {
        					out.print(b[i]);
        				}
        				return true;
        			}
        			return false;
        		}
        		for (int i = 1;i <= 4;i++)
        			if (!bo[i]) {
        				bo[i] = true;
        				b[dep] = a[i];
        				if (dfs(dep+1,now)) return true;
        				bo[i] = false;
        			}
        		return false;
        	}
            
            public void solve(InputReader in,PrintWriter out) {
            	s = in.next();
            	for (int i = 0;i < (int)s.length();i++) {
            		int key = s.charAt(i)-'0';
            		if (key==1 && cnt[1]==0) {
            			cnt[1] = 1;
            		}else if (key==6 && cnt[6]==0){
            			cnt[6] = 1;
            		}else if (key==8 && cnt[8]==0) {
            			cnt[8] = 1;
            		}else if (key==9 && cnt[9]==0) {
            			cnt[9] = 1;
            		}else {
            			cnt[key]++;
            			if (key!=0) {
            				out.print(key);
                			cur = cur * 10 + key;
                			cur = cur % 7;
            			}
            		}
            	}
            	dfs(1,cur);
            	
            	
            	for (int i = 1;i <= cnt[0];i++) {
            		out.print(0);
            	}
            }
        }
    
        
    
        static class InputReader{
            public BufferedReader br;
            public StringTokenizer tokenizer;
            
            public InputReader(InputStream ins) {
                br = new BufferedReader(new InputStreamReader(ins));
                tokenizer = null;
            }
            
            public String next(){
                while (tokenizer==null || !tokenizer.hasMoreTokens()) {
                    try {
                    tokenizer = new StringTokenizer(br.readLine());
                    }catch(IOException e) {
                        throw new RuntimeException(e);
                    }
                }
                return tokenizer.nextToken();
            }
            
            public int nextInt() {
                return Integer.parseInt(next());
            }
        }
    }
    
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  • 原文地址:https://www.cnblogs.com/AWCXV/p/10575474.html
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