【题目链接】:http://codeforces.com/contest/801/problem/A
【题意】
一个字符串只由VK组成;
让你修改一个字符;
使得剩下的字符串里面子串VK的个数最大;
【题解】
枚举修改哪一个字符;
然后获取剩余的字符里面VK的数的个数;
取MAX就好;
【Number Of WA】
0
【完整代码】
#include <bits/stdc++.h>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define ps push_back
#define fi first
#define se second
#define rei(x) cin >> x
#define pri(x) cout << x
#define ms(x,y) memset(x,y,sizeof x)
typedef pair<int,int> pii;
typedef pair<LL,LL> pll;
const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};
const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};
const double pi = acos(-1.0);
const int N = 110;
string s;
int ans;
int cnt(string ts)
{
int now = 0;
int len = ts.size();
rep1(i,1,len-1)
{
if (s[i-1]=='V'&&s[i]=='K')
now++;
}
return now;
}
int main()
{
//freopen("F:\rush.txt","r",stdin);
ios::sync_with_stdio(false);
cin >> s;
int len = s.size();
ans = cnt(s);
rep1(i,0,len-1)
{
char t = s[i];
if (t=='V')
s[i]='K';
else
s[i]='V';
ans = max(ans,cnt(s));
s[i] = t;
}
cout << ans << endl;
//printf("
%.2lf sec
", (double)clock() / CLOCKS_PER_SEC);
return 0;
}