【76.83%】【codeforces 554A】Kyoya and Photobooks

time limit per test2 seconds
memory limit per test256 megabytes
inputstandard input
outputstandard output
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled “a” to “z”, and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some “special edition” photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?

Please help Haruhi solve this problem.

Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.

Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.

Examples
input
a
output
51
input
hi
output
76
Note
In the first case, we can make ‘ab’,’ac’,…,’az’,’ba’,’ca’,…,’za’, and ‘aa’, producing a total of 51 distinct photo booklets.

【题目链接】:http://codeforces.com/contest/554/problem/A

【题解】

枚举26个字母,再枚举这个字母要插入到哪里;
判重的时候就直接用map搞。

【完整代码】

#include <bits/stdc++.h>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define rei(x) scanf("%d",&x)
#define rel(x) scanf("%I64d",&x)
#define pri(x) printf("%d",x)
#define prl(x) printf("%I64d",x)

typedef pair<int,int> pii;
typedef pair<LL,LL> pll;

//const int MAXN = x;
const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};
const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};
const double pi = acos(-1.0);

string s;
map <string,int> dic;

int main()
{
    //freopen("F:\rush.txt","r",stdin);
    LL ans = 0;
    cin >> s;
    int len = s.size();
    rep1(i,1,26)
    {
        char ke = i+'a'-1;
        rep1(j,0,len)
            {
                string temp = s;
                string st = "";
                st+=ke;
                temp.insert(j,st);
                if (!dic[temp])
                {
                    dic[temp] = 1;
                    ans++;
                }
            }
    }
    cout << ans << endl;
    return 0;
}