【链接】 我是链接,点我呀:)
【题意】
【题解】
各组数据之间有空行! 且最后一行后面没有空行! 然后就是用set来模拟就好。 删除的时候,不着急删除。 因为并不用时刻输出集合大小。所以只要遇到了把它删掉就Ok. 把相同的合并那里。我直接暴力合并了。 因为 150 30 100 30 不能看出一个整体的250 30的。。 要分步输出Trade信息的. 然后在合并的时候也要注意看里面有没有已经删除了的。 已经删除了的就直接跳过。。【代码】
#include <bits/stdc++.h>
using namespace std;
const int N = 1e4;
struct abc {
int num, price;
abc(int x = 0, int y = 0) :num(x), price(y) {}
};
abc re[N + 10];
struct setcmp1
{
bool operator () (const int &a, const int &b)
{
if (re[a].price == re[b].price)
return a < b;
else
return re[a].price > re[b].price;
}
};
struct setcmp2
{
bool operator () (const int &a, const int &b)
{
if (re[a].price == re[b].price)
return a < b;
else
return re[a].price < re[b].price;
}
};
set <int, setcmp1> buyset;//买的价格,越大越好
set <int, setcmp2> sellset;//卖的价格,越小越好
bool dele[N + 10];//用来记录某个交易是否被删除了。并不用时刻输出集合大小。所以只要遇到了把它删掉就Ok
int n;
void cl()
{
bool shan1, shan2;
do
{
shan1 = shan2 = false;
while (buyset.size() > 1 && dele[*buyset.begin()]) buyset.erase(buyset.begin()), shan1 = true;
while (sellset.size() > 1 && dele[*sellset.begin()]) sellset.erase(sellset.begin()), shan2 = true;
} while (shan1 || shan2);
}
void out()
{
int num1 = 0, num2 = 0;
int price1 = re[*buyset.begin()].price, price2 = re[*sellset.begin()].price;
for (auto it : buyset)
if (re[it].price == price1)
{
if (!dele[it]) num1 += re[it].num;
}
else break;
for (auto it : sellset)
if (re[it].price == price2)
{
if (!dele[it]) num2 += re[it].num;
}
else break;
printf("QUOTE %d %d - %d %d
", num1, price1, num2, price2);
}
int main()
{
//freopen("F:\rush.txt", "r", stdin);
int kk = 0;
while (~scanf("%d", &n))
{
if (kk > 0) puts("");
kk++;
re[N + 1].num = 0, re[N + 1].price = 0;
re[N + 2].num = 0, re[N + 2].price = 99999;
memset(dele, 0, sizeof dele);
buyset.clear(); sellset.clear();
buyset.insert(N + 1); sellset.insert(N + 2);
for (int i = 1; i <= n; i++)
{
char s[10];
scanf("%s", s);
switch (s[0])
{
case ('C'):
{
int x;
scanf("%d", &x);
dele[x] = true;
cl();//看看队首是不是要删掉
out();
break;
}
case ('B'):
{//买进
int num, price;
scanf("%d%d", &num, &price);
while (sellset.size() > 1 && num >0 && price >= re[*sellset.begin()].price)
{
int temp = min(re[*sellset.begin()].num, num), temp2 = re[*sellset.begin()].price;
num -= temp;
re[*sellset.begin()].num -= temp;
if (re[*sellset.begin()].num == 0)
{
sellset.erase(sellset.begin());
cl();
}
printf("TRADE %d %d
", temp, temp2);
}
re[i] = abc(num, price);
if (num != 0) buyset.insert(i);
out();
break;
}
case 'S':
{
//卖
int num, price;
scanf("%d%d", &num, &price);
while (buyset.size() > 1 && num >0 && price <= re[*buyset.begin()].price)
{
int temp = min(re[*buyset.begin()].num, num), temp2 = re[*buyset.begin()].price;
num -= temp;
re[*buyset.begin()].num -= temp;
if (re[*buyset.begin()].num == 0)
{
buyset.erase(buyset.begin());
cl();
}
printf("TRADE %d %d
", temp, temp2);
}
re[i] = abc(num, price);
if (num != 0) sellset.insert(i);
out();
break;
}
default:
break;
}
}
}
return 0;
}