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  • BZOJ 2763 [JLOI2011]飞行路线

    题面

    堆优的dijkstra裸题。

    努力把自己的代码写得更好看Ing

    //Twenty
    #include<cstdio>
    #include<cstdlib>
    #include<iostream>
    #include<algorithm>
    #include<cmath>
    #include<cstring>
    #include<queue>
    #include<vector>
    #include<ctime>
    const int maxn=10000+299;
    const int maxm=50000+299;
    typedef long long LL;
    using namespace std;
    
    struct node {
        int id,ct,k;
        node(){}
        node(int id,int ct,int k):id(id),ct(ct),k(k){}
        friend bool operator <(const node &A,const node &B) {
            return A.ct>B.ct;
        }
    }now,tp;
    
    inline int read() {
        char ch=getchar(); int ret=0;
        while(ch<'0'||ch>'9') ch=getchar();
        for(;ch>='0'&&ch<='9';ch=getchar()) ret=ret*10+ch-'0';
        return ret;
    }
    
    int fir[maxn],nxt[maxm*2],to[maxm*2],val[maxm*2],ecnt;
    void add(int u,int v,int w) {
        nxt[++ecnt]=fir[u]; fir[u]=ecnt; to[ecnt]=v; val[ecnt]=w;
        nxt[++ecnt]=fir[v]; fir[v]=ecnt; to[ecnt]=u; val[ecnt]=w;
    }
    
    int n,m,kk,s,t;
    void init() {
        n=read(); m=read(); kk=read();
        s=read(); t=read();
        for(int i=1;i<=m;i++) {
            int x,y,z;
            x=read(); y=read(); z=read();
            add(x,y,z);
        }
    }
    
    int ans=1e9,vis[maxn][11],dis[maxn][11];
    priority_queue<node>que;
    void dijkstra() {
        memset(dis,127,sizeof(dis));
        que.push(node(s,0,0));
        while(!que.empty()) {
            now=que.top();
            que.pop();
            int x=now.id,d=now.ct,k=now.k;
            vis[x][k]=1;
            for(int i=fir[x];i;i=nxt[i]) {
                int v=to[i];
                if(k<kk&&!vis[v][k+1]&&dis[v][k+1]>d) {
                    dis[v][k+1]=d;
                    que.push(node(v,d,k+1)); 
                }
                if(!vis[v][k]&&dis[v][k]>d+val[i]) {
                    dis[v][k]=d+val[i];
                    que.push(node(v,d+val[i],k)); 
                }
            }
        }
        for(int i=0;i<=kk;i++) ans=min(ans,dis[t][i]);
        printf("%d
    ",ans);
    }
    
    int main()
    {
        init();
        dijkstra();
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/Achenchen/p/7611460.html
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