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  • bzoj4161: Shlw loves matrixI

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    多项式取模优化k阶常系数线性递推的模板

    刚才的板子改了一下,wa了,,,先码这吧,下次再改。

     1 //Achen
     2 #include<algorithm>
     3 #include<iostream>
     4 #include<cstring>
     5 #include<cstdlib>
     6 #include<vector>
     7 #include<cstdio>
     8 #include<queue>
     9 #include<cmath>
    10 #include<set>
    11 #include<map>
    12 #define Formylove return 0
    13 #define For(i,a,b) for(int i=(a);i<=(b);i++)
    14 #define Rep(i,a,b) for(int i=(a);i>=(b);i--)
    15 const int N=4007,p=1000000007;
    16 typedef long long LL;
    17 typedef double db;
    18 using namespace std;
    19 LL a[N],f[N],n,k;
    20 
    21 template<typename T>void read(T &x)  {
    22     char ch=getchar(); x=0; T f=1;
    23     while(ch!='-'&&(ch<'0'||ch>'9')) ch=getchar();
    24     if(ch=='-') f=-1,ch=getchar();
    25     for(;ch>='0'&&ch<='9';ch=getchar()) x=x*10+ch-'0'; x*=f;
    26 }
    27 
    28 LL rs[N],bs[N];
    29 void mul(LL a[],LL b[],LL c[]) {
    30     static LL tp[N];
    31     int up=(k<<1);
    32     For(i,0,up) tp[i]=0;
    33     For(i,0,k-1) For(j,0,k-1)
    34         (tp[i+j]+=a[i]*b[j]%p)%=p; 
    35     Rep(i,up,k) { 
    36         For(j,1,k) (tp[i-j]+=f[j]*tp[i]%p)%=p;
    37         tp[i]=0;
    38     }
    39     For(i,0,up) c[i]=tp[i]; 
    40 }
    41 
    42 void ksm(LL b) {
    43     while(b) {
    44         if(b&1) mul(rs,bs,rs);
    45         mul(bs,bs,bs);
    46         b>>=1;    
    47     }
    48 }
    49 
    50 //#define ANS
    51 int main() {
    52 #ifdef ANS
    53     freopen("shanghai.in","r",stdin);
    54     freopen("shanghai.out","w",stdout);
    55 #endif
    56     read(n); read(k);
    57     For(i,1,k) read(f[i]);
    58     For(i,1,k) { read(a[i]); (a[i]+=p)%=p; }
    59     if(n<k) { 
    60         printf("%lld
    ",a[n+1]); 
    61         return 0;
    62     }
    63     rs[0]=1; bs[1]=1;
    64     ksm(n);
    65     LL ans=0;
    66     For(i,0,k-1) (ans+=rs[i]*a[i+1]%p)%=p;
    67     printf("%lld
    ",ans);
    68     Formylove;
    69 }
    View Code
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  • 原文地址:https://www.cnblogs.com/Achenchen/p/9507826.html
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