这个拆队比赛的题目质量优秀过头了吧？
1 #include <bits/stdc++.h> 2 using namespace std; 3 const int maxn = 5e6 + 10; 4 typedef long long LL; 5 6 int n, p, q, m; 7 unsigned int SA, SB, SC; 8 unsigned int rng61() { 9 SA ^= SA << 16; 10 SA ^= SA >> 5; 11 SA ^= SA << 1; 12 unsigned int t = SA; 13 SA = SB; 14 SB = SC; 15 SC ^= t ^ SA; 16 return SC; 17 } 18 stack<int> st, ma; 19 LL gen() { 20 LL ret = 0; 21 while(!st.empty()) st.pop(), ma.pop(); 22 st.push(0), ma.push(0); 23 scanf("%d%d%d%d%u%u%u", &n, &p, &q, &m, &SA, &SB, &SC); 24 for (int i = 1; i <= n; i++) { 25 if (rng61() % (p + q) < p) st.push(rng61() % m + 1), ma.push(max(st.top(), ma.top())); 26 else if(st.size() > 1) st.pop(), ma.pop(); 27 ret ^= (LL) i * ma.top(); 28 } 29 return ret; 30 } 31 int main() { 32 int T; 33 scanf("%d", &T); 34 for(int kase = 1; kase <= T; ++kase) { 35 printf("Case #%d: %lld ", kase, gen()); 36 } 37 return 0; 38 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 double x[111], y[111]; 4 5 const double pi = acos(-1); 6 double sqr(double x) {return x * x;} 7 double dis(int i, int j) { 8 return sqrt(sqr(x[i] - x[j]) +sqr(y[i] - y[j])); 9 } 10 11 int main() { 12 int T; 13 scanf("%d", &T); 14 for(int kase = 1; kase <= T; ++kase) { 15 int n; 16 scanf("%d", &n); 17 for(int i = 0; i <= n; ++i) scanf("%lf %lf", x + i, y + i); 18 double ans = 0; 19 for(int j = 0; j < n; ++j) { 20 int i = (j - 1 + n) % n, k = (j + 1) % n; 21 double d1 = dis(i, j), d2 = dis(j, k), d3 = dis(i, k); 22 double cos_theta = (sqr(d1) + sqr(d2) -sqr(d3)) / 2 / d1 / d2, theta = acos(cos_theta); 23 ans += dis(j, n) * (pi - theta); 24 } 25 printf("Case #%d: %.3f ", kase, ans); 26 } 27 return 0; 28 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 char A[55], B[55], C[55]; 4 5 int main() { 6 int T; 7 scanf("%d", &T); 8 for(int kase = 1; kase <= T; ++kase) { 9 int n, m; 10 scanf("%d %d %s %s %s", &n, &m, A + 1, B + 1, C + 1); 11 int b = (B[1] - A[1] + 26) % 26; 12 for(int i = 1; i <= m; ++i) C[i] = (C[i] - 'A' - b + 26) % 26 + 'A'; 13 printf("Case #%d: ", kase); 14 puts(C + 1); 15 } 16 return 0; 17 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 4 int main() { 5 int T; 6 scanf("%d", &T); 7 for(int kase = 1; kase <= T; ++kase) { 8 int n, m; 9 scanf("%d %d", &n, &m); 10 printf("Case #%d: %.6f %.6f ", kase, n == 1 ? 1 : 0.5, (m + 1) / 2.0 / m); 11 } 12 return 0; 13 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 const int maxn = 1e5 + 10; 4 int a[maxn]; 5 6 int cnt, rt; 7 struct node { 8 int f; 9 vector<int> d, ch; 10 void init(int fa, int x) { 11 f = fa; 12 d.clear(), ch.clear(); 13 d.push_back(x); 14 } 15 } tr[maxn]; 16 17 void ins(int p, int x) { 18 if(tr[p].d.size() == 3) { 19 int f = tr[p].f; 20 vector<int> cpy_d, cpy_ch; 21 cpy_d.swap(tr[p].d), cpy_ch.swap(tr[p].ch); 22 if(p == rt) { 23 tr[rt=++cnt].init(0, cpy_d[1]); 24 tr[++cnt].init(rt, cpy_d[0]); 25 tr[p].init(rt, cpy_d[2]); 26 tr[rt].ch.push_back(cnt), tr[rt].ch.push_back(p); 27 if(cpy_ch.size()) { 28 tr[cnt].ch.push_back(cpy_ch[0]), tr[cpy_ch[0]].f = cnt; 29 tr[cnt].ch.push_back(cpy_ch[1]), tr[cpy_ch[1]].f = cnt; 30 tr[p].ch.push_back(cpy_ch[2]), tr[cpy_ch[2]].f = p; 31 tr[p].ch.push_back(cpy_ch[3]), tr[cpy_ch[3]].f = p; 32 } 33 p = rt; 34 } 35 else { 36 tr[p].init(f, cpy_d[0]); 37 tr[++cnt].init(f, cpy_d[2]); 38 tr[f].d.push_back(cpy_d[1]); 39 sort(tr[f].d.begin(), tr[f].d.end()); 40 tr[f].ch.push_back(cnt); 41 for(int i = tr[f].ch.size() - 1; i > 1; --i) { 42 if(tr[f].ch[i-1] != p) swap(tr[f].ch[i-1], tr[f].ch[i]); 43 else break; 44 } 45 if(cpy_ch.size()) { 46 tr[p].ch.push_back(cpy_ch[0]), tr[cpy_ch[0]].f = p; 47 tr[p].ch.push_back(cpy_ch[1]), tr[cpy_ch[1]].f = p; 48 tr[cnt].ch.push_back(cpy_ch[2]), tr[cpy_ch[2]].f = cnt; 49 tr[cnt].ch.push_back(cpy_ch[3]), tr[cpy_ch[3]].f = cnt; 50 } 51 p = f; 52 } 53 } 54 if(tr[p].ch.size() == 0) { 55 tr[p].d.push_back(x); 56 sort(tr[p].d.begin(), tr[p].d.end()); 57 } 58 else { 59 if(x < tr[p].d[0]) ins(tr[p].ch[0], x); 60 else if(x > tr[p].d[tr[p].d.size()-1]) ins(tr[p].ch[tr[p].ch.size()-1], x); 61 else { 62 for(int i = 1; i < tr[p].d.size(); ++i) 63 if(x < tr[p].d[i]) {ins(tr[p].ch[i], x); break;} 64 } 65 } 66 } 67 68 void dfs(int p) { 69 for(int i = 0; i < tr[p].d.size(); ++i) 70 printf("%d%c", tr[p].d[i], i == tr[p].d.size() - 1 ? ' ' : ' '); 71 for(int i = 0; i < tr[p].ch.size(); ++i) 72 dfs(tr[p].ch[i]); 73 } 74 75 int main() { 76 int T; 77 scanf("%d", &T); 78 for(int kase = 1; kase <= T; ++kase) { 79 int n; 80 scanf("%d", &n); 81 for(int i = 1; i <= n; ++i) scanf("%d", a + i); 82 cnt = rt = 1, tr[rt].init(0, a[1]); 83 for(int i = 2; i <= n; ++i) ins(rt, a[i]); 84 printf("Case #%d: ", kase); 85 dfs(rt); 86 } 87 return 0; 88 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 int G[222][222], w[222], nid[222]; 4 int u[22222], v[22222], qw[22222], qid[22222], ans[22222]; 5 bool cmp1(int i, int j) {return w[i] < w[j];} 6 bool cmp2(int i, int j) {return qw[i] < qw[j];} 7 void floyd(int x, int n) { 8 for(int i = 1; i <= n; ++i) 9 for(int j = 1; j <= n; ++j) 10 G[i][j] = min(G[i][j], G[i][x] + G[x][j]); 11 } 12 int main() { 13 int T; 14 scanf("%d", &T); 15 for(int kase = 1; kase <= T; ++kase) { 16 int n, q; 17 scanf("%d %d", &n, &q); 18 for(int i = 1; i <= n; ++i) scanf("%d", w + i), nid[i] = i; 19 sort(nid + 1, nid + 1 + n, cmp1); 20 for(int i = 1; i <= n; ++i) 21 for(int j = 1; j <= n; ++j) 22 scanf("%d", &G[i][j]); 23 for(int i = 1; i <= q; ++i) scanf("%d %d %d", u + i, v + i, qw + i), qid[i] = i; 24 sort(qid + 1, qid + 1 + q, cmp2); 25 int p = 0; 26 for(int i = 1; i <= q; ++i) { 27 while(p < n && w[nid[p+1]] <= qw[qid[i]]) floyd(nid[++p], n); 28 ans[qid[i]] = G[u[qid[i]]][v[qid[i]]]; 29 } 30 printf("Case #%d: ", kase); 31 for(int i = 1; i <= q; ++i) printf("%d ", ans[i]); 32 } 33 return 0; 34 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 const int maxn = 1e5 + 10; 4 vector<int> G[maxn], D[maxn]; 5 int n, k; 6 7 typedef long long LL; 8 const LL INF = 1e18; 9 LL f[maxn][105]; 10 int leaf[maxn]; 11 void dfs(int x, int fa, int w) { 12 leaf[x] = 0; 13 for(int i = 1; i <= k; ++i) f[x][i] = INF; 14 if(G[x].size() == 1) f[x][1] = (LL) w * (k - 1), leaf[x]++; 15 for(int i = 0; i < G[x].size(); ++i) { 16 int to = G[x][i], nw = D[x][i]; 17 if(to == fa) continue; 18 dfs(to, x, nw); 19 for(int j = min(k, leaf[x] + leaf[to]); j >= 0; --j) 20 for(int p = max(0, j - leaf[x]); p <= min(leaf[to], j); ++p) 21 f[x][j] = min(f[x][j], f[x][j-p] + f[to][p] + (LL) w * (j * (k - j) - (j - p) * (k - j + p))); 22 leaf[x] += leaf[to]; 23 } 24 } 25 26 int main() { 27 int T; 28 scanf("%d", &T); 29 for(int kase = 1; kase <= T; ++kase) { 30 scanf("%d %d", &n, &k); 31 for(int i = 1; i <= n; ++i) G[i].clear(), D[i].clear(); 32 for(int i = 1; i < n; ++i) { 33 int u, v, w; 34 scanf("%d %d %d", &u, &v, &w); 35 G[u].push_back(v), D[u].push_back(w); 36 G[v].push_back(u), D[v].push_back(w); 37 } 38 if(n == 2) { 39 printf("Case #%d: %d ", kase, k == 2 ? D[1][0] : 0); 40 continue; 41 } 42 int rt = 0; 43 for(int i = 1; i <= n; ++i) 44 if(G[i].size() >= 2) rt = i; 45 dfs(rt, 0, 0); 46 printf("Case #%d: %lld ", kase, f[rt][k]); 47 } 48 return 0; 49 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 typedef long long LL; 4 const int maxn = 1e5 + 10; 5 int a[maxn], b[maxn], c[maxn], d[maxn]; 6 bool cmp(int i, int j) {return (LL) c[j] * b[i] > c[i] * b[j];} 7 int main() { 8 int T; 9 scanf("%d", &T); 10 for(int kase = 1; kase <= T; ++kase) { 11 int n; 12 scanf("%d", &n); 13 for(int i = 1; i <= n; ++i) { 14 scanf("%d %d", a + i, b + i); 15 int sum = 0; 16 for(int j = 1; ; ++j) { 17 sum += j; 18 if(sum >= a[i]) {c[i] = j; break;} 19 } 20 d[i] = i; 21 } 22 sort(d + 1, d + 1 + n, cmp); 23 LL ans = 0, sum = 0; 24 for(int i = 1; i <= n; ++i) { 25 int x = d[i]; 26 sum += c[x]; 27 ans += sum * b[x]; 28 } 29 printf("Case #%d: %lld ", kase, ans); 30 } 31 return 0; 32 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 typedef long long LL; 4 LL po[55]; 5 6 int main() { 7 int T; 8 scanf("%d", &T); 9 for(int kase = 1; kase <= T; ++kase) { 10 int n, k, q; 11 scanf("%d %d %d", &n, &k, &q); 12 if(k >= n - 1) { 13 LL ans = 1; 14 for(int i = 1; i <= n; ++i) ans = ans * i % q; 15 printf("Case #%d: %lld ", kase, ans); 16 continue; 17 } 18 po[0] = 1; 19 for(int i = 1; i <= n; ++i) po[i] = po[i-1] * (k + 1) % q; 20 LL ans = (po[n-k] + (LL) (n - k - 1) * (n - k) / 2 % q * po[n-k-1]) % q; 21 for(int i = 1; i <= n - k - 2; ++i) ans = (ans + po[i] * i) % q; 22 for(int i = 1; i <= k; ++i) ans = ans * i % q; 23 printf("Case #%d: %lld ", kase, ans); 24 } 25 return 0; 26 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 typedef long long LL; 4 const int maxn = 1e5 + 10; 5 LL x[maxn], y[maxn], xp, yp, xq, yq; 6 LL cross(LL x1, LL y1, LL x2, LL y2) { 7 return x1 * y2 - x2 * y1; 8 } 9 bool cmp1(int i, int j) { 10 return cross(x[i] - xp, y[i] - yp, x[j] - xp, y[j] - yp) > 0; 11 } 12 bool cmp2(int i, int j) { 13 return cross(x[i] - xq, y[i] - yq, x[j] - xq, y[j] - yq) < 0; 14 } 15 16 int a[maxn], b[maxn], c[maxn], f[maxn], pre[maxn]; 17 int lowbit(int s) { 18 return s & (-s); 19 } 20 void modify(int i, int x) { 21 while (i < maxn) { 22 if(x != -1 && (c[i] == -1 || f[x] >= f[c[i]])) { 23 if(c[i] == -1 || f[x] > f[c[i]]) c[i] = x; 24 else if(x < c[i]) c[i] = x; 25 } 26 i += lowbit(i); 27 } 28 return; 29 } 30 int query(int i) { 31 int ret = -1; 32 while (i > 0) { 33 if(c[i] != -1 && (ret == -1 || f[c[i]] >= f[ret])) { 34 if(ret == -1 || f[c[i]] > f[ret]) ret = c[i]; 35 else if(c[i] < ret) ret = c[i]; 36 } 37 i -= lowbit(i); 38 } 39 return ret; 40 } 41 const int INF = 1e9; 42 void print(int x) { 43 while(x != -1) { 44 printf("%d ", x); 45 x = pre[x]; 46 } 47 } 48 vector<int> id[2]; 49 int main() { 50 int T; 51 scanf("%d", &T); 52 for(int kase = 1; kase <= T; ++kase) { 53 scanf("%lld %lld %lld %lld", &xp, &yp, &xq, &yq); 54 int n; 55 scanf("%d", &n); 56 id[0].clear(), id[1].clear(); 57 for(int i = 1; i <= n; ++i) { 58 scanf("%lld %lld", x + i, y + i); 59 if(cross(xq - xp, yq - yp, x[i] - xp, y[i] - yp) > 0) id[0].push_back(i); 60 else id[1].push_back(i); 61 } 62 int M[2]; 63 for(int i = 0; i <= 1; ++i) { 64 sort(id[i].begin(), id[i].end(), cmp1); 65 for(int j = 0; j < id[i].size(); ++j) { 66 if(j == 0) a[id[i][j]] = 1; 67 else if(cmp1(id[i][j-1], id[i][j])) a[id[i][j]] = a[id[i][j-1]] + 1; 68 else a[id[i][j]] = a[id[i][j-1]]; 69 } 70 sort(id[i].begin(), id[i].end(), cmp2); 71 for(int j = 0; j < id[i].size(); ++j) { 72 if(j == 0) b[id[i][j]] = 1; 73 else if(cmp2(id[i][j-1], id[i][j])) b[id[i][j]] = b[id[i][j-1]] + 1; 74 else b[id[i][j]] = b[id[i][j-1]]; 75 } 76 M[i] = 0; 77 for(int j = 0; j <= id[i].size(); ++j) c[j] = -1; 78 for(int j = 0; j < id[i].size(); ++j) { 79 int k = j; 80 while(k + 1 < id[i].size() && b[id[i][k+1]] == b[id[i][k]]) k++; 81 for(int p = j; p <= k; ++p) { 82 int o = id[i][p]; 83 pre[o] = query(a[o] - 1); 84 f[o] = pre[o] == -1 ? 1 : f[pre[o]] + 1; 85 M[i] = max(M[i], f[o]); 86 } 87 for(int p = j; p <= k; ++p) { 88 int o = id[i][p]; 89 modify(a[o], o); 90 } 91 j = k; 92 } 93 swap(xp, xq), swap(yp, yq); 94 } 95 printf("Case #%d: %d ", kase, max(M[0], M[1])); 96 for(int i = 1; i <= n; ++i) { 97 if(f[i] == max(M[0], M[1])) { 98 print(i); break; 99 } 100 } 101 } 102 return 0; 103 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 typedef long long LL; 4 LL a[55], f[1<<20]; 5 vector<int> G[55]; 6 7 int main() { 8 int T; 9 scanf("%d", &T); 10 for(int kase = 1; kase <= T; ++kase) { 11 int n, m, q; 12 scanf("%d %d %d", &n, &m, &q); 13 for(int i = 1; i <= n; ++i) scanf("%lld", a + i), G[i].clear(); 14 for(int i = 1; i <= m; ++i) { 15 int u, v; 16 scanf("%d %d", &u, &v); 17 G[u].push_back(v); 18 G[v].push_back(u); 19 } 20 if(n == 1) {printf("Case #%d: %lld ", kase, (1 + a[1]) % q); continue;} 21 int k1 = n / 2, k2 = n - k1; 22 for(int i = 0; i < (1 << k1); ++i) { 23 int ok = 1; 24 LL sum = 1; 25 for(int j = 1; j <= k1; ++j) { 26 if(i & (1 << (j - 1))) sum = sum * a[j] % q; 27 for(int k = 0; k < G[j].size(); ++k) { 28 int to = G[j][k]; 29 if(to > k1) continue; 30 if(!(i & (1 << (j - 1))) && !(i & (1 << (to - 1)))) {ok = 0; break;} 31 } 32 if(!ok) break; 33 } 34 f[i] = ok ? sum : 0; 35 } 36 for(int i = 0; i < k1; ++i) 37 for(int j = 0; j < (1 << k1); ++j) 38 if(j & (1 << i)) f[j^(1<<i)] = (f[j^(1<<i)] + f[j]) % q; 39 LL ans = 0; 40 for(int i = 0; i < (1 << k2); ++i) { 41 int ok = 1, msk = 0; 42 LL sum = 1; 43 for(int j = k1 + 1; j <= n; ++j) { 44 if(i & (1 << (j - k1 - 1))) sum = sum * a[j] % q; 45 for(int k = 0; k < G[j].size(); ++k) { 46 int to = G[j][k]; 47 if(to > k1) { 48 if(!(i & (1 << (j - k1 - 1))) && !(i & (1 << (to - k1 - 1)))) {ok = 0; break;} 49 } 50 else if(!(i & (1 << (j - k1 - 1)))) msk |= 1 << (to - 1); 51 } 52 if(!ok) break; 53 } 54 if(ok) ans = (ans + sum * f[msk]) % q; 55 } 56 printf("Case #%d: %lld ", kase, ans); 57 } 58 return 0; 59 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 const int maxn = 1e5 + 10; 4 typedef long long LL; 5 6 // seg 7 int M[maxn<<2], cnt[maxn<<2], tag[maxn<<2]; 8 void gather(int p) { 9 M[p] = min(M[p << 1], M[p << 1 | 1]); 10 if (M[p << 1] == M[p << 1 | 1]) cnt[p] = cnt[p << 1] + cnt[p << 1 | 1]; 11 else if (M[p << 1] < M[p << 1 | 1]) cnt[p] = cnt[p << 1]; 12 else cnt[p] = cnt[p << 1 | 1]; 13 } 14 void push(int p) { 15 if (tag[p]) { 16 tag[p << 1] += tag[p]; 17 tag[p << 1 | 1] += tag[p]; 18 M[p << 1] += tag[p]; 19 M[p << 1 | 1] += tag[p]; 20 tag[p] = 0; 21 } 22 } 23 void build(int p, int l, int r) 24 { 25 tag[p] = 0, cnt[p] = 1; 26 if(l < r) 27 { 28 int mid = (l + r) >> 1; 29 build(p<<1, l, mid); 30 build(p<<1|1, mid + 1, r); 31 gather(p); 32 } 33 else M[p] = 0; 34 } 35 void modify(int p, int tl, int tr, int l, int r, int v) { 36 if (tl > tr) return; 37 if (tr < l || r < tl) return; 38 if (l <= tl && tr <= r) { 39 tag[p] += v; 40 M[p] += v; 41 return; 42 } 43 push(p); 44 int mid = (tl + tr) >> 1; 45 modify(p << 1, tl, mid, l, r, v); 46 modify(p << 1 | 1, mid + 1, tr, l, r, v); 47 gather(p); 48 } 49 int query(int p, int tl, int tr, int l, int r) { 50 if (tl > tr) return 0; 51 if (tr < l || r < tl) return 0; 52 if (l <= tl && tr <= r) return M[p] == 0 ? cnt[p] : 0; 53 push(p); 54 int mid = (tl + tr) >> 1; 55 return query(p << 1, tl, mid, l, r) + query(p << 1 | 1, mid + 1, tr, l, r); 56 } 57 58 int a[maxn]; 59 map<int, int> pre; 60 stack<int> up, down; 61 int main() { 62 int T; 63 scanf("%d", &T); 64 for(int kase = 1; kase <= T; ++kase) { 65 int n; 66 scanf("%d", &n); 67 build(1, 1, n); 68 pre.clear(); 69 while(!up.empty()) up.pop(); 70 while(!down.empty()) down.pop(); 71 LL ans = 0; 72 for(int i = 1; i <= n; ++i) { 73 scanf("%d", a + i); 74 while(up.size() && a[up.top()] > a[i]) { 75 int t = up.top(); up.pop(); 76 if(up.size()) modify(1, 1, n, up.top() + 1, t, a[t] - a[i]); 77 else modify(1, 1, n, 1, t, a[t] - a[i]); 78 } 79 while(down.size() && a[down.top()] < a[i]) { 80 int t = down.top(); down.pop(); 81 if(down.size()) modify(1, 1, n, down.top() + 1, t, a[i] - a[t]); 82 else modify(1, 1, n, 1, t, a[i] - a[t]); 83 } 84 up.push(i), down.push(i); 85 if(pre.find(a[i]) != pre.end()) modify(1, 1, n, pre[a[i]] + 1, i - 1, -1); 86 else modify(1, 1, n, 1, i - 1, -1); 87 pre[a[i]] = i; 88 ans += query(1, 1, n, 1, i); 89 } 90 printf("Case #%d: %lld ", kase, ans); 91 } 92 return 0; 93 }
1 #include <bits/stdc++.h> 2 using namespace std; 3 typedef long long LL; 4 5 // myyfft 6 const int max0 = 262144 << 1; 7 const double PI = acos(-1); 8 int N, L, bitrev[max0 + 5]; 9 struct cp { 10 double x, y; 11 cp() : x(0), y(0) {} 12 cp(const double &_x, const double &_y) : x(_x), y(_y) {} 13 } w[max0 + 5]; 14 inline cp operator + (const cp &a, const cp &b) {return cp(a.x + b.x, a.y + b.y);} 15 inline cp operator - (const cp &a, const cp &b) {return cp(a.x - b.x, a.y - b.y);} 16 inline cp operator * (const cp &a, const cp &b) {return cp(a.x * b.x - a.y * b.y, a.x * b.y + a.y * b.x);} 17 inline cp conj(const cp &a) {return cp(a.x, -a.y); } 18 void fft(cp *a, const int &n) { 19 for (int i = 0; i < n; ++i) if (i < bitrev[i]) swap(a[i], a[bitrev[i]]); 20 for (int i = 2, lyc = n >> 1; i <= n; i <<= 1, lyc >>= 1) { 21 for (int j = 0; j < n; j += i) { 22 cp *l = a + j, *r = a + j + (i >> 1), *p = w; 23 for (int k = 0; k < i >> 1; ++k) { 24 cp tmp = *r * *p; 25 *r = *l - tmp, *l = *l + tmp; 26 ++l, ++r, p += lyc; 27 } 28 } 29 } 30 } 31 inline void fft_prepare() { 32 for (int i = 0; i < N; ++i) bitrev[i] = bitrev[i >> 1] >> 1 | ((i & 1) << (L - 1)); 33 for (int i = 0; i < N; ++i) w[i] = cp(cos(2 * PI * i / N), sin(2 * PI * i / N)); 34 } 35 inline void conv(int *x, int *y, int *z, int mod) { 36 for (int i = 0; i < N; ++i) (x[i] += mod) %= mod, (y[i] += mod) %= mod; 37 static cp a[max0 + 5], b[max0 + 5]; 38 static cp dfta[max0 + 5], dftb[max0 + 5], dftc[max0 + 5], dftd[max0 + 5]; 39 for (int i = 0; i < N; ++i) a[i] = cp(x[i] & 32767, x[i] >> 15); 40 for (int i = 0; i < N; ++i) b[i] = cp(y[i] & 32767, y[i] >> 15); 41 fft(a, N), fft(b, N); 42 for (int i = 0; i < N; ++i) { 43 int j = (N - i) & (N - 1); 44 static cp da, db, dc, dd; 45 da = (a[i] + conj(a[j])) * cp(0.5, 0); 46 db = (a[i] - conj(a[j])) * cp(0, -0.5); 47 dc = (b[i] + conj(b[j])) * cp(0.5, 0); 48 dd = (b[i] - conj(b[j])) * cp(0, -0.5); 49 dfta[j] = da * dc; 50 dftb[j] = da * dd; 51 dftc[j] = db * dc; 52 dftd[j] = db * dd; 53 } 54 for (int i = 0; i < N; ++i) a[i] = dfta[i] + dftb[i] * cp(0, 1); 55 for (int i = 0; i < N; ++i) b[i] = dftc[i] + dftd[i] * cp(0, 1); 56 fft(a, N), fft(b, N); 57 for (int i = 0; i < N; ++i) { 58 int da = (LL) (a[i].x / N + 0.5) % mod; 59 int db = (LL) (a[i].y / N + 0.5) % mod; 60 int dc = (LL) (b[i].x / N + 0.5) % mod; 61 int dd = (LL) (b[i].y / N + 0.5) % mod; 62 z[i] = (da + ((LL) (db + dc) << 15) + ((LL) dd << 30)) % mod; 63 } 64 } 65 66 LL fac[max0], inv_fac[max0]; 67 LL fp(LL a, LL b, LL mod) { 68 LL ret = 1LL; 69 while (b) { 70 if (b & 1) ret = ret * a % mod; 71 a = a * a % mod; 72 b >>= 1; 73 } 74 return ret; 75 } 76 77 LL S[max0], f[max0], pre[max0], suf[max0]; 78 int main() { 79 int T; 80 scanf("%d", &T); 81 for(int kase = 1; kase <= T; ++kase) { 82 int n, m, mod; 83 scanf("%d %d %d", &n, &m, &mod); 84 fac[0] = 1; 85 for(int i = 1; i <= n + m; ++i) fac[i] = fac[i-1] * i % mod; 86 inv_fac[0] = inv_fac[1] = 1; 87 for(int i = 2; i <= n + m; i++) inv_fac[i] = (mod - (mod / i) * inv_fac[mod % i] % mod) % mod; 88 for(int i = 3; i <= n + m; ++i) inv_fac[i] = inv_fac[i] * inv_fac[i-1] % mod; 89 static int a[max0 + 5], b[max0 + 5], c[max0 + 5]; 90 for(int i = 0; i <= n; ++i) a[i] = (i % 2 ? mod - 1 : 1) * inv_fac[i] % mod; 91 for(int i = 0; i <= n; ++i) b[i] = fp(i, n, mod) * inv_fac[i] % mod; 92 L = 0; 93 for (; (1 << L) < n + n + 1; ++L); 94 N = 1 << L; 95 for(int i = n + 1; i < N; ++i) a[i] = b[i] = 0; 96 fft_prepare(); 97 conv(a, b, c, mod); 98 for(int i = 0; i <= n; ++i) S[i] = (c[i] + mod) * fac[i] % mod; 99 for(int i = 0; i <= n; ++i) a[i] = S[i] * inv_fac[i] % mod; 100 for(int i = 0; i <= n + m; ++i) b[i] = fp(i, m, mod) * inv_fac[i] % mod; 101 L = 0; 102 for (; (1 << L) < n + n + m + 1; ++L); 103 N = 1 << L; 104 for(int i = n + 1; i < N; ++i) a[i] = 0; 105 for(int i = n + m + 1; i < N; ++i) b[i] = 0; 106 fft_prepare(); 107 conv(a, b, c, mod); 108 for(int i = 0; i <= n + m; ++i) f[i] = (c[i] + mod) * fac[i] % mod; 109 LL ans = 0; 110 pre[0] = suf[n + m + 2] = 1; 111 for(int i = 1; i <= n + m + 1; ++i) pre[i] = pre[i - 1] * (mod - i) % mod; 112 for(int i = n + m + 1; i >= 1; --i) suf[i] = suf[i + 1] * (mod - i) % mod; 113 for(int i = 1; i <= n + m + 1; ++i) { 114 LL x = pre[i - 1] * suf[i + 1] % mod * inv_fac[i-1] % mod * inv_fac[n + m + 1 - i] % mod; 115 if((n + m + 1 - i) % 2) x = x * (mod - 1) % mod; 116 ans = (ans + x * f[i - 1]) % mod; 117 } 118 if((n + m) % 2) ans = ans * (mod - 1) % mod; 119 printf("Case #%d: %lld ", kase, ans); 120 } 121 return 0; 122 }