zoukankan      html  css  js  c++  java
  • unity里的向量

    y                         = b                         + a * x

    transform.position = transform.position + (mousPosition - transform.position.normalized * 0.1f);

    利用y = ax + b 这种直线方程来控制transform.position向mousPosition 慢慢移动。a(0.1f)为时间

    用点乘求两个向量夹角:

    Vector2 a = new Vector2 (1.0f,0.0f);
    Vector2 b = new Vector2 (2.0f,2 * Mathf.Sqrt(3)).normalized;//必须要是normalized的才能这样用 否的算出的结果会出错
    float d = Vector2.Dot (a,b);
    float ang = Mathf.Acos (d) * Mathf.Rad2Deg;
    Debug.Log (ang);

    求两个向量的距离 

    Vector3 aa = new Vector3 (1, 0, 0);
    Vector3 bb = new Vector3 (0,Mathf.Sqrt(3),0);
    Debug.Log(Vector3.Distance (aa,bb));

    得到2

    向量差乘(计算两个向量夹角)(这个没看懂记住这种用法就好,实际使用的情况较少)

    Vector3 aa = new Vector3 (1, 1, 0);
    Vector3 bb = new Vector3 (0,Mathf.Sqrt(3),0);
    // Debug.Log(Vector3.Distance (aa,bb));
    Vector3 c = Vector3.Cross (aa,bb);
    Vector3 cc = Vector3.Cross (bb,aa);
    float ang = Mathf.Asin (Vector3.Distance(Vector3.zero,Vector3.Cross(aa.normalized,bb.normalized)))*Mathf.Rad2Deg;
    Debug.Log (ang);

  • 相关阅读:
    poj1243(经典dp)
    hdu3485(递推)
    poj2479(dp)
    hdu3415(单调队列)
    hdu1876(dp)
    hdu1042(大数模板)
    hdu2125(数学)
    hdu1992(递推)
    android api文档:intent阅读笔记
    bitmap相关工具类
  • 原文地址:https://www.cnblogs.com/Akishimo/p/4969752.html
Copyright © 2011-2022 走看看