题意:
思路:
- 最大值最小二分哈曼顿距离建边
- 二分图01染色判断是否合理
代码:
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define forn(i,n) for(int i=0;i<n;i++)
#define for1(i,n) for(int i=1;i<=n;i++)
#define IO ios::sync_with_stdio(false);cin.tie(0)
const int mod = 1e9+7;
const int maxn = 5005;
int color[maxn],n,ans,res;
pair<int,int>a[maxn];
ll powmod(ll a,ll b){
ll res = 1;
for(;b;b>>=1){
if(b&1) (res*=a)%=mod;
(a*=a)%=mod;
}
return res;
}
bool dfs(int u,int len,bool cur){
color[u] = cur;
forn(i,n){
if(u==i) continue;
int v = abs(a[i].first-a[u].first)+abs(a[i].second-a[u].second);
if(v<=len) continue;
if(color[i]==-1) {
if(!dfs(i,len,cur^1)) return 0;
}
else if(color[i]==cur) return 0;
}
return 1;
}
bool check(int len){
forn(i,n) color[i] = -1;
int cnt = 0;
forn(i,n)if(color[i]==-1){
cnt++;
if(!dfs(i,len,0)) return 0;
}
ans = len,res= cnt;
return 1;
}
int main(){
IO;cin>>n;
forn(i,n) cin>>a[i].first>>a[i].second;
int l = 0,r = 1e4;
while(l<=r){
int mid = l+r>>1;
if(check(mid)) r = mid-1;
else l = mid+1;
}
res = powmod(2,res);
cout << ans <<'
'<<res;
return 0;
}