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  • 数据库脚本面试题1

    写出sql语句取出每门功课成绩最好的学生数据

    准备阶段:

    创建表语句

    1 SET ANSI_NULLS ONGOSET QUOTED_IDENTIFIER ONGOSET ANSI_PADDING ONGOCREATE TABLE [dbo].[stuscore]
    2 ( [name] [varchar](50)   COLLATE Chinese_PRC_CI_AS   NULL,    
    3 [subject] [varchar](50)   COLLATE Chinese_PRC_CI_AS   NULL,    
    4 [score] [int]   NULL,   
    5 [stuid] [int]    NULL) 
    6 ON [PRIMARY] 
    7 GO
    8 SET ANSI_PADDING OFF

    插入数据

    1 insert into dbo.stuscore values ('张三','数学',89,1);
    2 insert into dbo.stuscore values ('张三','语文',80,1);
    3 insert into dbo.stuscore values ('张三','英语',70,1);
    4 insert into dbo.stuscore values ('李四','数学',90,2);
    5 insert into dbo.stuscore values ('李四','语文',70,2);
    6 insert into dbo.stuscore values ('李四','英语',80,2);

    问题:

    1.计算每个人的总成绩并排名(要求显示字段:姓名,总成绩)

    1 select name,SUM(score) as allscore from dbo.stuscore
    2 group by name 
    3 order by allscore;

    2.计算每个人的总成绩并排名(要求显示字段: 学号,姓名,总成绩)

    1 select stuid,name,SUM(score) as allscore from dbo.stuscore 
    2 group by name,stuid 
    3 order by allscore;

    3.计算每个人单科的最高成绩(要求显示字段: 学号,姓名,课程,最高成绩)

    1 select t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,
    2 (select stuid,max(score) as maxscore from stuscore group by stuid) t2 
    3 where t1.stuid=t2.stuid and t1.score=t2.maxscore;

    4.计算每个人的平均成绩(要求显示字段: 学号,姓名,平均成绩)

     1 select stuid,name,AVG(score) avgscore from dbo.stuscore 2 group by stuid,name; 

    5.列出各门课程成绩最好的学生(要求显示字段: 学号,姓名,科目,成绩) 

    1 select t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,(
    2 select subject,MAX(score) as maxscore from stuscore group by subject)t2
    3 where t1.subject = t2.subject and t1.score = t2.maxscore;

    6.列出各门课程成绩最好的两位学生(要求显示字段: 学号,姓名,科目,成绩) 

    1 select  t1.* from stuscore t1 where t1.stuid in (
    2 select top 2 stuid from stuscore where subject = t1.subject order by score desc)
    3 order by t1.subject;

    7.列出数学成绩的排名(要求显示字段:学号,姓名,成绩,排名)

    1 select stuid,name,score,
    2 (select count(*) from stuscore t1 where subject ='数学' and t1.score > t2.score)+1 as 名次 from stuscore t2  
    3 where subject='数学' order by score desc;
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  • 原文地址:https://www.cnblogs.com/Andy-Blog/p/15209219.html
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