AjaxUploader使用：文件保存到数据库

1.存储到Buffer中

Void Uploader_FileUploaded(object sender,UploaderEventArgs args)

{

    byte[] data = new byte[args.FileSize];

    using(Stream stream = args.OpenStream())

{

    stream.Read(data,0,data.Length);

}

}

2.将Buffer中的内容存储到数据库中