Description
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
- One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
- One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.
Sample Input
3 BAPC BAPC AZA AZAZAZA VERDI AVERDXIVYERDIAN
Sample Output
1 3 0
给两个字符串,求第一个字符串在第二个中出现的次数
KMP最精华即next数组
参考博客:http://blog.csdn.net/zz_ylolita/article/details/50650391
1 #include<cstdio> 2 #include<iostream> 3 #include<cstring> 4 #include<string.h> 5 using namespace std; 6 7 char p[10005]; 8 char s[1000005]; 9 int next[10005]; 10 int lenp,lens; 11 12 void getnext() 13 { 14 next[0]=-1; 15 int j=-1; 16 for (int i=1;i<lenp;i++) 17 { 18 while (j>-1 && p[j+1]!=p[i]) j=next[j]; 19 if (p[j+1]==p[i]) j++; 20 next[i]=j; 21 } 22 } 23 int kmp() 24 { 25 int j=-1,count=0; 26 for (int i=0;i<lens;i++) 27 { 28 while (j>-1 && p[j+1]!=s[i]) j=next[j]; 29 if (p[j+1]==s[i]) j++; 30 if (j==lenp-1) 31 { 32 count++; 33 j=next[j]; 34 } 35 } 36 return count; 37 } 38 39 int main() 40 { 41 int T; 42 scanf("%d",&T); 43 while(T--) 44 { 45 cin>>p>>s; 46 lenp=strlen(p); 47 lens=strlen(s); 48 getnext(); 49 printf("%d ",kmp()); 50 } 51 return true; 52 }