Problem Description
As we all know that RXD is a life winner, therefore he always goes out, dating with his female friends.
Nevertheless, it is a pity that his female friends don't like extremely hot temperature. Due to this fact, they would not come out if it is higher than 35 degrees.
RXD is omni-potent, so he could precisely predict the temperature in the next t days, but he is poor in counting.
He wants to know, how many days are there in the next t days, in which he could go out and date with his female friends.
Nevertheless, it is a pity that his female friends don't like extremely hot temperature. Due to this fact, they would not come out if it is higher than 35 degrees.
RXD is omni-potent, so he could precisely predict the temperature in the next t days, but he is poor in counting.
He wants to know, how many days are there in the next t days, in which he could go out and date with his female friends.
Input
There is only one test case.
The first line consists of one integer t.
The second line consists of t integers ci which means the temperature in the next t days.
1≤t≤1000
0≤ci≤50
The first line consists of one integer t.
The second line consists of t integers ci which means the temperature in the next t days.
1≤t≤1000
0≤ci≤50
Output
Output an integer which means the answer.
Sample Input
5
33 34 35 36 37
Sample Output
3
题意：要你判断给出的温度有几个在35度及以下
1 #include<cstdio> 2 #include<iostream> 3 #include<cmath> 4 #include<cstring> 5 using namespace std; 6 #define MAXN 3005 7 8 9 10 int main() 11 { 12 int t,res=0,tmp; 13 scanf("%d",&t); 14 while(t--) 15 { 16 scanf("%d",&tmp); 17 if(tmp<=35) 18 res++; 19 } 20 printf("%d ",res); 21 return 0; 22 }