zoukankan      html  css  js  c++  java
  • [React] When to useReducer instead of useState

    useState is typically simpler at first than useReducer (you can even implement useState using useReducer), but there's one scenario where useReducer is almost certainly better than useState:

    When one element of your state relies on the value of another element of your state in order to update: useReducer

    More information: KcD's blog

    import React from 'react'
    import ReactDOM from 'react-dom'
    
    function undoReducer(state, action) {
      const {past, present, future} = state
      const {type, newPresent} = action
    
      switch (type) {
        case 'UNDO': {
          if (past.length === 0) return state
    
          const previous = past[past.length - 1]
          const newPast = past.slice(0, past.length - 1)
          return {
            past: newPast,
            present: previous,
            future: [present, ...future],
          }
        }
        case 'REDO': {
          if (future.length === 0) return state
          const next = future[0]
          const newFuture = future.slice(1)
          return {
            past: [...past, present],
            present: next,
            future: newFuture,
          }
        }
        case 'SET': {
          if (newPresent === present) {
            return state
          }
          return {
            past: [...past, present],
            present: newPresent,
            future: [],
          }
        }
        case 'RESET': {
          return {
            past: [],
            present: newPresent,
            future: [],
          }
        }
        default: {
          throw new Error(`Unhandled action type: ${type}`)
        }
      }
    }
    
    function useUndo(initialPresent) {
      const [state, dispatch] = React.useReducer(undoReducer, {
        past: [],
        present: initialPresent,
        future: [],
      })
    
      const canUndo = state.past.length !== 0
      const canRedo = state.future.length !== 0
    
      const undo = React.useCallback(() => {
        dispatch({type: 'UNDO'})
      }, [])
    
      const redo = React.useCallback(() => {
        dispatch({type: 'REDO'})
      }, [])
    
      const set = React.useCallback(newPresent => {
        dispatch({type: 'SET', newPresent})
      }, [])
    
      const reset = React.useCallback(newPresent => {
        dispatch({type: 'RESET', newPresent})
      }, [])
    
      return [state, {set, reset, undo, redo, canUndo, canRedo}]
    }
    
    function App() {
      const [state, {set}] = useUndo('first')
    
      React.useEffect(() => {
        set('second')
      }, [set])
    
      React.useEffect(() => {
        set('third')
      }, [set])
    
      return <pre>{JSON.stringify(state, null, 2)}</pre>
    }
    
    ReactDOM.render(<App />, document.getElementById('root'))
  • 相关阅读:
    Python爬虫连载9-JS加密之“盐”​、ajax请求
    Java连载86-List集合详解
    HTML连载69-透视属性以及其他属性练习
    Java连载85-集合的Contains和Remove方法
    Python爬虫连载8-JS加密(一)
    Java连载84-Collection的常用方法、迭代器
    HTML连载68-形变中心点、形变中心轴
    Java连载83-单向链表、双向链表、collections常用方法
    [刷题] 447 Number of Boomerangs
    [刷题] 454 4Sum II
  • 原文地址:https://www.cnblogs.com/Answer1215/p/12464013.html
Copyright © 2011-2022 走看看