删除数组中name属性重复的对象，展示最后一个（删除数组中重复的对象）

调用：

let results = deleteObject(obj);
console.log(results);

方法：

function deleteObject (obj) {
var uniques = [];
var stringify = {};

for (var i = 0; i < obj.length; i++) {

var str = JSON.stringify(obj[i]['name']);

if (!stringify.hasOwnProperty(str)) {
uniques.push(obj[i]);
stringify[str] = true;
}
}
uniques = uniques;
return uniques;
}

es6写法：

export const deleteObject = (obj) => {
var uniques = [];
var stringify = {};
for (var i = 0; i < obj.length; i++) {

var str = JSON.stringify(obj[i]['name']);

if (!stringify.hasOwnProperty(str)) {
uniques.push(obj[i]);
stringify[str] = true;
}
}
uniques = uniques;
return uniques;
};

或

function deteleObject(obj) {
    var uniques = [];
    var stringify = {};
    for (var i = 0; i < obj.length; i++) {
        var keys = Object.keys(obj[i]);
        keys.sort(function(a, b) {
            return (Number(a) - Number(b));
        });
        var str = '';
        for (var j = 0; j < keys.length; j++) {
            str += JSON.stringify(keys[j]);
            str += JSON.stringify(obj[i][keys[j]]);
        }
        if (!stringify.hasOwnProperty(str)) {
            uniques.push(obj[i]);
            stringify[str] = true;
        }
    }
    uniques = uniques;
    return uniques;
}