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  • POJ 3461 Oulipo【KMP】【模板题】(找出第一个字符串在第二个字符串中出现次数)

    Oulipo
    Time Limit: 1000MS   Memory Limit: 65536K
    Total Submissions: 42886   Accepted: 17234

    Description

    The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:

    Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

    Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

    So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A''B''C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

    Input

    The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

    • One line with the word W, a string over {'A''B''C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
    • One line with the text T, a string over {'A''B''C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

    Output

    For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

    Sample Input

    3
    BAPC
    BAPC
    AZA
    AZAZAZA
    VERDI
    AVERDXIVYERDIAN

    Sample Output

    1
    3
    0

    Source


    找出第一个字符串在第二个字符串中出现次数

    #include <iostream>
    #include <cmath>
    #include <algorithm>
    #include <cstdio>
    #include <stdlib.h>
    #include <string>
    #include <cstring>
    #include <map>
    #include <set>
    #include <queue>
    #include <stack>
    #define INF 0x3f3f3f3f
    #define ms(x,y) memset(x,y,sizeof(x))
    using namespace std;
    
    typedef long long ll;
    
    const double pi = acos(-1.0);
    const int mod = 1e9 + 7;
    const int maxn = 1e5 + 10;
    
    int nextval[100010];
    char s[1000100],p[1000010];
    
    //p为模式串
    void getnext(char p[], int nextval[])      //朴素kmp,nextval[i]即为1~i-1的最长前后缀长度
    {
        int len=strlen(p);
        int i=0,j=-1;
        nextval[0]=-1;
        while(i<len)
        {
            if(j==-1||p[i]==p[j])
            {
                nextval[++i]=++j;
            }
            else
                j=nextval[j];
        }
    }
    
    //在s中找p出现的次数
    int KMP(char s[], char p[], int nextval[])
    {
        getnext(p,nextval);
        int ans=0;
        int i=0;    //s下标
        int j=0;    //p下标
        int s_len=strlen(s);
        int p_len=strlen(p);
        while(i<s_len&&j<p_len)
        {
            if(j==-1||s[i]==p[j])
            {
                i++;
                j++;
            }
            else
                j=nextval[j];
    
            if(j==p_len)
            {
                j=nextval[j];   //注意这个优化比较重要
                ans++;
            }
        }
        return ans;
    }
    
    int main()
    {
        //freopen("in.txt","r",stdin);
        //freopen("out.txt","w",stdout);
        int n;
        scanf("%d",&n);
        while(n--)
        {
            ms(p,0);
            ms(s,0);
            scanf(" %s %s",p,s);
            printf("%d
    ",KMP(s,p,nextval));
        }
        return 0;
    }

    Fighting~
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  • 原文地址:https://www.cnblogs.com/Archger/p/8451568.html
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