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  • Leetcode-967 Numbers With Same Consecutive Differences(连续差相同的数字)

     1 #define _for(i,a,b) for(int i = (a);i < (b);i ++)
     2 class Solution
     3 {
     4     public:
     5         vector<int> rnt;
     6         void dfs(int N,int K,int h,string s)
     7         {
     8             if(h==N)
     9             {
    10                 stringstream ss;
    11                 ss<<s;
    12                 int tmp;
    13                 ss>>tmp;
    14                 rnt.push_back(tmp);
    15                 return ;
    16             }
    17             if(h==0)
    18             {
    19                 _for(i,0,10)
    20                 {
    21                     s+=i+'0';
    22                     dfs(N,K,h+1,s);
    23                     s.pop_back();
    24                 }
    25             }
    26             else
    27             {
    28                 _for(i,0,10)
    29                 {
    30                     if(s[h-1]=='0'&&h==1)
    31                         break;
    32                     if(abs(i+'0'-s[h-1])==K)
    33                     {
    34                         s+=i+'0';
    35                         dfs(N,K,h+1,s);
    36                         s.pop_back();
    37                     }
    38                 }
    39             }
    40         }
    41         vector<int> numsSameConsecDiff(int N, int K)
    42         {
    43             rnt.clear();
    44             string s;
    45             dfs(N,K,0,s);
    46             return rnt;
    47         }
    48 };
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  • 原文地址:https://www.cnblogs.com/Asurudo/p/10199734.html
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