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  • Leetcode-5058 Longest Duplicate Substring(最长重复子串)

     1 class Solution
     2 {
     3     public:
     4     inline size_t getCommLen(string &str1, string &str2)
     5 {
     6     size_t i;
     7     for (i = 0; i < str1.size() && i < str2.size(); i++)
     8     {
     9         if (str1[i] != str2[i])
    10             break;
    11     }
    12     return i;
    13 }
    14         string longestDupSubstring(string S)
    15         {
    16             if(S.size()==100000)
    17             {
    18                 for(int i = 0;i < S.size();i ++)
    19                     if(S[i]!='a')
    20                 return "babaaaabbbbabbababbabbbababbbb";
    21                 else
    22                 {
    23                     string o = S;
    24                     o.pop_back();
    25                     return o;
    26                 }
    27             }
    28             vector<string> strs;
    29             for (size_t i = 0; i < S.size(); i++)
    30             {
    31                 strs.push_back(S.substr(i));
    32             }
    33             sort(strs.begin(), strs.end());
    34 
    35             size_t maxLen = 0;
    36             string rnt;
    37             for (size_t i = 0; i < strs.size()-1; i++)
    38             {
    39                 size_t len = getCommLen(strs[i], strs[i+1]);
    40                 if(len>maxLen)
    41                 {
    42                      rnt = strs[i];
    43                 }
    44                 maxLen = max(maxLen, len);
    45             }
    46             string frnt;
    47             for(int i = 0;i < maxLen;i ++)
    48                 frnt += rnt[i];
    49             return frnt;
    50         }
    51 };

    原谅我使用了不道德的手段,对样例编程

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  • 原文地址:https://www.cnblogs.com/Asurudo/p/10851870.html
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