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  • 【算法总结】二叉树

    模板:

    1.先序遍历三种方法

    1)迭代:

    class Solution {
    public:
        /**
         * @param root: The root of binary tree.
         * @return: Preorder in vector which contains node values.
         */    
        vector<int> preorderTraversal(TreeNode *root) {
            vector<int> res;
            stack<TreeNode*> stack;
            
            if (root == NULL) {
                return res;
            }
            
            stack.push(root);
            while (!stack.empty()) {
                TreeNode *node = stack.top();
                stack.pop();
                res.push_back(node->val);
                if (node->right != NULL) {
                    stack.push(node->right);
                }
                if (node->left != NULL) {
                    stack.push(node->left);
                }
            }
            
            return res;
        }
    };

    2)递归:

    class Solution {
    public:
        void traversal(TreeNode *root, vector<int>& res) {
            if (root == NULL) {
                return;
            }
            
            res.push_back(root->val);
            traversal(root->left, res);
            traversal(root->right, res);
        }
        vector<int> preorderTraversal(TreeNode *root) {
            vector<int> res;
            traversal(root, res);
            
            return res;
        }
    };

    3)分治:

    class Solution {
    public:    
        vector<int> preorderTraversal(TreeNode *root) {
            vector<int> res;
            if (root == NULL) {
                return res;
            }
            
            vector<int> left = preorderTraversal(root->left);
            vector<int> right = preorderTraversal(root->right);
            
            res.push_back(root->val);
            res.insert(res.end(), left.begin(), left.end());
            res.insert(res.end(), right.begin(), right.end());
            
            return res;
        }
    };

     模板2:DFS:

    1) Traverse

    class Solution {
    public:
        void traverse(TreeNode *root) {
            if (root == NULL) {
                return;
            }
            
            // do something with root
            traverse(root->left);
            // do something with root
            traverse(root->right);
            // do something with root
        }
    };

    2) Divide and Conquer

    class Solution {
    public:
        ResultType traversal(TreeNode * root) {
            if (root == NULL) {
                // do something and return
            }
            
            // Divide
            ResultType left = traversal(root->left);
            ResultType right = traversal(root->right);
            
            // Conquer
            ResultType result = Merge from left and right
            
            return result;
        }
    };

     栈实现非递归DFS

    //preOrderTraversal
    void preOrderTraversal1(TreeNode* root) {
        if (root == NULL) {
            return;
        }
        
        stack<TreeNode*> s;
        TreeNode* p = root;
        
        while (!s.empty() || p) {
            while (p) {
                func(p);
                s.push(p);
                p = p->left;
            }
            if (!s.empty()) {
                p = s.top();
                s.pop();
                p = p->right;
            }
        }
    }
    void preOrderTraversal2(TreeNode* root) {
        if (root == NULL) {
            return;
        }
        
        stack<TreeNode*> s;
        s.push(root);
        
        while (!s.empty()) {
            TreeNode* tmp = s.top();
            s.pop();
            func(tmp);
            if (tmp->right) {
                s.push(tmp->right);
            }
            if (tmp->left) {
                s.push(tmp->left);
            }
        }
    }
    void preOrderTraversal3(TreeNode* root) {
        if (root == NULL) {
            return;
        }
        
        stack<TreeNode*> s;
        s.push(root);
        TreeNode* tmp = root;
        
        while (!s.empty()) {
            func(tmp);
            if (tmp->right) {
                s.push(tmp->right);
            }
            if (tmp->left) {
                s.push(tmp->left);
            } else {
                p = s.top();
                s.pop();
            }
        }
    }
    //inOrderTraversal
    void inOrderTraversal1(TreeNode* root) {
        if (root == NULL) {
            return;
        }
        
        stack<TreeNode*> s;
        TreeNode* p = root;
        
        while (!s.empty() || p) {
            while (p) {
                s.push(p);
                p = p->left;
            }
            if (!s.empty()) {
                p = s.top();
                s.pop();
                func(p);
                p = p->right;
            }
        }
    }
    //postOrderTraversal
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  • 原文地址:https://www.cnblogs.com/Atanisi/p/6827023.html
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