zoukankan      html  css  js  c++  java
  • 1008. Elevator (20)

    The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.

    For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.

    Input Specification:

    Each input file contains one test case. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100.

    Output Specification:

    For each test case, print the total time on a single line.

    Sample Input:

    3 2 3 1
    

    Sample Output:

    41


     1 import java.util.*;
     2 
     3 public class Main {
     4 
     5     public static void main(String[] args) {
     6         Scanner in = new Scanner(System.in);
     7         int curFloor=0;
     8         int N=in.nextInt();
     9         int time=5*N;
    10         int minus=0;
    11         while (N-->0){
    12             minus=in.nextInt()-curFloor;
    13             curFloor+=minus;
    14             time+=minus>0?minus*6:minus*-4;
    15         }
    16         System.out.println(time);
    17     }
    18 }
  • 相关阅读:
    ACM2023
    Archlinux系统运维
    Apache2配置腾讯云SSL证书
    奇异值分解SVD
    剑指offer-不用加减乘除做加法
    负载均衡与缓存
    leetcode简单题6
    python 函数
    Mac-常用命令与快捷键
    GOM通区插件-支持GOM绝对路径-读取配置项-分割字符等功能。不定期更新
  • 原文地址:https://www.cnblogs.com/BJUT-2010/p/5569372.html
Copyright © 2011-2022 走看看