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  • HDU 4001 To Miss Our Children Time DP

    排序后DP,注意要用long long 的地方。

    //#pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push_back(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("d:\in.txt","r",stdin);
       // freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    
    const int maxn=1001;
    const int mod=100000007;
    
    struct block
    {
        int a,b,c,d;
        bool operator < (const block &x) const
        {
            if(a!=x.a)
                return a<x.a;
            else if(b!=x.b)
                return b<x.b;
            else if(d!=x.d)
                return d>x.d;
            else return c>x.c;
        }
    };
    
    block da[maxn];
    
    ll dp[maxn];
    ll f(int k,int n)
    {
        if(k>n)return 0;
        if(dp[k]>=0)return dp[k];
        ll maxx=0;
        for(int i=k+1;i<=n;i++)
        {
            if(da[i].d==0){
                if(da[i].a>=da[k].a&&da[i].b>=da[k].b)
                    maxx=max(maxx,f(i,n)+da[i].c);
            }else if(da[i].d==1){
                if(da[i].a>=da[k].a&&da[i].b>=da[k].b&&(ll)da[i].a*da[i].b>(ll)da[k].a*da[k].b)
                    maxx=max(maxx,f(i,n)+da[i].c);
            }else if(da[i].d==2){
                if(da[i].a>da[k].a&&da[i].b>da[k].b)
                    maxx=max(maxx,f(i,n)+da[i].c);
            }
        }
        return dp[k]=maxx;
    }
    int main()
    {
        //freopen("in.txt","r",stdin);
        int n;
        da[0]=(block){0,0,0,0};
        while(cin>>n&&n)
        {
            for(int i=1;i<=n;i++)
            {
                scanf("%d%d%d%d",&da[i].a,&da[i].b,&da[i].c,&da[i].d);
                if(da[i].a<da[i].b)swap(da[i].a,da[i].b);
            }
            sort(da+1,da+1+n);
            memset(dp,-1,sizeof(dp));
            ll num=f(0,n);
            cout<<num<<endl;
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3437894.html
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