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  • POJ 2441 Arrange the Bulls 状态DP

    //#pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("d:\in1.txt","r",stdin);
        freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    
    int dp[1<<20];
    int like[22][22];
    int n,m;
    int f()
    {
        dp[0]=1;
        for(int i=1;i<=n;i++)
        {
            for(int st=(1<<m)-1;st>=0;st--) if(dp[st]!=0)
            {
                for(int j=0;j<m;j++) if(like[i][j]&&!((1<<j)&st))
                {
                    dp[st|(1<<j)]+=dp[st];
                    //printf("dp[%d]=%d
    ",st|(1<<j),dp[st|(1<<j)]);
                }
    
                dp[st]=0;
            }
        }
        int ans=0;
        for(int st=0;st<(1<<m);st++)
            if(dp[st]!=-1)ans+=dp[st];
        return ans;
    }
    int main()
    {
        while(scanf("%d%d",&n,&m)!=EOF)
        {
            memset(like,0,sizeof(like));
            memset(dp,0,sizeof(dp));
            for(int i=1;i<=n;i++)
            {
                int p;
                scanf("%d",&p);
                for(int j=1;j<=p;j++)
                {
                    int x;
                    scanf("%d",&x);
                    like[i][x-1]=1;
                }
            }
            int res=f();
            printf("%d
    ",res);
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3608473.html
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