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  • UVA 10917 Walk Through the Forest 最短路 + DP

    求出最短路后,如果d[A]<d[B] 则B可以走向A

    是个DAG。

    //#pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("d:\in1.txt","r",stdin);
        freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    
    struct Edge
    {
        int from,to,dist;
    };
    struct HeapNode
    {
        int d,u;
        bool operator < (const HeapNode &ant ) const
        {
            return d>ant.d;
        }
    };
    
    const int maxn=1005;
    int n;
    vector<int> g[maxn];
    vector<Edge> edge;
    
    void InitGraph()
    {
        for(int i=1;i<=n;i++)
            g[i].clear();
        edge.clear();
    }
    
    void AddEdge(int u,int v,int w)
    {
        Edge e=(Edge){u,v,w};
        edge.push_back(e);
        g[u].push_back(edge.size()-1);
    }
    
    int done[maxn];
    int d[maxn];
    
    void Dijksta(int s)
    {
        priority_queue<HeapNode> q;
        q.push((HeapNode){0,s});
        for(int i=1;i<=n;i++)
            d[i]=INF;
        d[s]=0;
        memset(done,0,sizeof(done));
        while(!q.empty())
        {
            HeapNode x=q.top();q.pop();
            if(done[x.u])continue;
            done[x.u]=1;
            for(int i=0;i<g[x.u].size();i++)
            {
                Edge &e=edge[g[x.u][i]];
                if(d[e.to]>d[x.u]+e.dist)
                {
                    d[e.to]=d[x.u]+e.dist;
                    q.push((HeapNode){d[e.to],e.to});
                }
            }
        }
    }
    
    int dp[maxn];
    int f(int u)
    {
        if(u==2)return 1;
        if(dp[u]>=0)return dp[u];
        dp[u]=0;
        for(int i=0;i<g[u].size();i++)
        {
            int v=edge[g[u][i]].to;
            if(d[v]<d[u])
                dp[u]+=f(v);
        }
        return dp[u];
    }
    int DP()
    {
        memset(dp,-1,sizeof(dp));
        return f(1);
    }
    
    int main()
    {
        while(scanf("%d",&n)!=EOF&&n)
        {
            InitGraph();
            int m;
            scanf("%d",&m);
            for(int i=1;i<=m;i++)
            {
                int u,v,w;
                scanf("%d%d%d",&u,&v,&w);
                AddEdge(u,v,w);
                AddEdge(v,u,w);
            }
            Dijksta(2);
            int res=DP();
            printf("%d
    ",res);
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3632899.html
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