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  • UVA 1048 Low Cost Air Travel 最短路

    以(i,j) 为结点建图,其中i表示目前已经到过行程单上的前i个城市,j是目前在哪个城市。

    注意

    1.起点是行程单上的第一个城市

    2.城市的编号会很大,要重新编号。

    //#pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("in.txt","r",stdin);
        //freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    struct HeapNode
    {
        int d,u;
        bool operator < (const HeapNode &ant) const
        {
            return d>ant.d;
        }
    };
    struct Edge
    {
        int from,to;
        int dist;
        int ticket_id;
    };
    const int maxn=5005;
    struct Dijksta
    {
        int n;
        vector<int> g[maxn];
        vector<Edge> edge;
        int done[maxn];
        int d[maxn];
        int p[maxn];
        void init(int n)
        {
            this->n=n;
            for(int i=1;i<=n;i++)
                g[i].clear();
            edge.clear();
        }
    
        void add(int u,int v,int w,int id)
        {
            //if(u>maxn||v>maxn)while(1);
            Edge e=(Edge){u,v,w,id};
            edge.push_back(e);
            g[u].push_back(edge.size()-1);
        }
    
        void solve(int s)
        {
            for(int i=1;i<=n;i++)
                d[i]=INF;
            d[s]=0;
            p[s]=-1;
            memset(done,0,sizeof(done));
            priority_queue<HeapNode> q;
            q.push((HeapNode){0,s});
            while(!q.empty())
            {
                HeapNode x=q.top();q.pop();
                if(done[x.u])continue;
                int u=x.u;
                done[u]=1;
                for(int i=0;i<g[u].size();i++)
                {
                    Edge &e=edge[g[u][i]];
                    if(d[u]+e.dist<d[e.to])
                    {
                        d[e.to]=d[u]+e.dist;
                        p[e.to]=g[u][i];
                        q.push((HeapNode){d[e.to],e.to});
                    }
                }
            }
        }
        void output(int e)
        {
            stack<int> s;
            for(e=p[e];e!=-1;e=p[edge[e].from])
                s.push(edge[e].ticket_id);
            if(!s.empty()&&s.top()==0)s.pop();
            while(!s.empty())
                printf(" %d",s.top()),s.pop();
            printf("
    ");
        }
    }solver;
    
    int id[11][maxn];
    int n;
    int ID(int a,int b)
    {
        int &x=id[a][b];
        if(x==0)x=++n;
        return x;
    }
    
    int ticket[22][12],iti[22][12];
    int tickcost[22];
    int ticnum[22],itinum[22];
    int alltick,alliti;
    
    
    void process(int ca,int trip)
    {
        solver.init(5002);
        memset(id,0,sizeof(id));
        n=0;
    
        for(int i=0;i<itinum[trip];i++)
            for(int j=1;j<=400;j++)if(i!=0||j!=iti[trip][1])
                for(int k=1;k<=alltick;k++)if(ticket[k][1]==j)
                    for(int l=2,num=i;l<=ticnum[k];l++)
                    {
                        if(iti[trip][num+1]==ticket[k][l])num++;
                        solver.add(ID(i,j),ID(num,ticket[k][l]),tickcost[k],k);
                    }
        solver.solve(ID(1,iti[trip][1]));
        int x=itinum[trip];
        int idx=ID(x,iti[trip][x]);
        printf("Case %d, Trip %d: Cost = %d
    ",ca,trip,solver.d[idx]);
        printf("  Tickets used:");
        solver.output(idx);
    }
    int readint(){int x;scanf("%d",&x);return x;}
    int read()
    {
        scanf("%d",&alltick);
        if(alltick==0)return 0;
        int cnt=0;
        map<int,int> ma;
        for(int i=1;i<=alltick;i++)
        {
            tickcost[i]=readint();
            ticnum[i]=readint();
            for(int j=1;j<=ticnum[i];j++)
            {
                int x=readint();
                if(ma[x]==0)ma[x]=++cnt;
                ticket[i][j]=ma[x];
            }
        }
        scanf("%d",&alliti);
        for(int i=1;i<=alliti;i++)
        {
            itinum[i]=readint();
            for(int j=1;j<=itinum[i];j++)
            {
                int x=readint();
                if(ma[x]==0)ma[x]=++cnt;
                iti[i][j]=ma[x];
            }
        }
        return 1;
    }
    int main()
    {
        //debug();
        int ca=0;
        while(read())
        {
            ca++;
            for(int i=1;i<=alliti;i++)
                process(ca,i);
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3632967.html
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