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  • POJ 1979 Red and Black DFS

    简单DFS。

    //#pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("in.txt","r",stdin);
        //freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    
    const int maxn=25;
    char g[maxn][maxn];
    int dx[]={0,0,1,-1};
    int dy[]={1,-1,0,0};
    
    int vis[maxn][maxn];
    void dfs(int x,int y,int &num)
    {
        num++;
        vis[x][y]=1;
        for(int d=0;d<4;d++)
        {
            int nx=x+dx[d];
            int ny=y+dy[d];
            if(g[nx][ny]=='.'&&!vis[nx][ny])
                dfs(nx,ny,num);
        }
    }
    
    int main()
    {
        int n,m;
        while(scanf("%d%d",&m,&n)!=EOF&&n)
        {
            memset(g,'#',sizeof(g));
            for(int i=1;i<=n;i++)
                scanf("%s",g[i]+1);
            int num=0;
            memset(vis,0,sizeof(vis));
            for(int i=1;i<=n;i++)
                for(int j=1;j<=m;j++)
                    if(g[i][j]=='@')
                        dfs(i,j,num);
            printf("%d
    ",num);
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3647733.html
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