Description
Input
Output
Sample Input
![](http://www.lydsy.com/JudgeOnline/images/1452_4.jpg)
Sample Output
1
2
2
HINT
题解:
二维的树状数组啊+一维的颜色状态,然后直接做就好……实际上比照一维的树状数组就是多了一个for循环,然后查询操作的时候就相当于查询某一矩阵的大小,树状数组起到一个类似前缀和的作用。
1 #include <iostream> 2 #include <cstdio> 3 #include <algorithm> 4 #include <cstring> 5 #define lowbit(x) x&(-x) 6 using namespace std; 7 const int MAXN = 301; 8 int a[MAXN][MAXN], Tree[101][MAXN][MAXN]; 9 int n, m; 10 void Modify(int x, int y, int s, int tar) 11 { 12 int i, j; 13 for (i = x; i <= n; i += lowbit(i)) 14 for (j = y; j <= m; j += lowbit(j)) 15 Tree[s][i][j] += tar; 16 } 17 inline int Query(int x, int y, int s) 18 { 19 int i, j; 20 int sum = 0; 21 for (i = x; i; i -= lowbit(i)) 22 for (j = y; j; j -= lowbit(j)) 23 sum += Tree[s][i][j]; 24 return sum; 25 } 26 int main(int argc, char *argv[]) 27 { 28 int c, i, j, x, Q, op, y; 29 int x1, y1, x2, y2; 30 int ans; 31 scanf("%d%d", &n, &m); 32 for (i = 1; i <= n; i++) 33 for (j = 1; j <= m; j++) 34 { 35 scanf("%d", &a[i][j]); 36 Modify(i, j, a[i][j], 1); 37 } 38 scanf("%d", &Q); 39 while (Q--) 40 { 41 scanf("%d", &op); 42 if (op == 1) 43 { 44 scanf("%d%d%d", &x, &y, &c); 45 Modify(x, y, a[x][y], -1); 46 a[x][y] = c; 47 Modify(x, y, a[x][y], 1); 48 } 49 else if (op == 2) 50 { 51 scanf("%d%d%d%d%d", &x1, &x2, &y1, &y2, &c); 52 ans = 0; 53 ans = Query(x1 - 1, y1 - 1, c) + Query(x2, y2, c) - Query(x1 - 1, y2, c) - Query(x2 , y1 - 1, c); 54 printf("%d ", ans); 55 } 56 } 57 return 0; 58 }