编程用JAVA解析XML的方式？

用SAX方式解析XML，XML文件如下：

庄周 信息学院 6258113 男,1955年生,博士，95年调入郑州大学 事件回调类SAXHandler.java import java.io.; import java.util.Hashtable; import org.xml.sax.; public class SAXHandler extends HandlerBase { private Hashtable table = new Hashtable(); private String currentElement = null; private String currentValue = null; public void setTable(Hashtable table) { this.table = table; } public Hashtable getTable() { return table; } public void startElement(String tag, AttributeList attrs) throws SAXException { currentElement = tag; } public void characters(char[] ch, int start, int length) throws SAXException { currentValue = new String(ch, start, length); } public void endElement(String name) throws SAXException { if (currentElement.equals(name)) table.put(currentElement, currentValue); } } JSP内容显示源码,SaxXml.jsp: <%@ page errorPage=ErrPage.jsp contentType=text/html;charset=GB2312 %> <%@ page import=java.io.* %> <%@ page import=java.util.Hashtable %> <%@ page import=org.w3c.dom.* %> <%@ page import=org.xml.sax.* %> <%@ page import=javax.xml.parsers.SAXParserFactory %> <%@ page import=javax.xml.parsers.SAXParser %> <%@ page import=SAXHandler %> <% File file = new File(c:people.xml); FileReader reader = new FileReader(file); Parser parser; SAXParserFactory spf = SAXParserFactory.newInstance(); SAXParser sp = spf.newSAXParser(); SAXHandler handler = new SAXHandler(); sp.parse(new InputSource(reader), handler); Hashtable hashTable = handler.getTable(); out.println(); out.println( + ); out.println( + ); out.println( + ); out.println( + ); out.println(
教师信息表
姓名 + (String)hashTable.get(new String(name)) +
学院 + (String)hashTable.get(new String(college))+
电话 + (String)hashTable.get(new String(telephone)) +
备注 + (String)hashTable.get(new String(notes)) +
); %>