zoukankan      html  css  js  c++  java
  • 牛客SQL题解-获取员工其当前的薪水比其manager当前薪水还高的相关信息

    题目描述

    获取员工其当前的薪水比其manager当前薪水还高的相关信息,当前表示to_date='9999-01-01',
    结果第一列给出员工的emp_no,
    第二列给出其manager的manager_no,
    第三列给出该员工当前的薪水emp_salary,
    第四列给该员工对应的manager当前的薪水manager_salary
    CREATE TABLE `dept_emp` (
    `emp_no` int(11) NOT NULL,
    `dept_no` char(4) NOT NULL,
    `from_date` date NOT NULL,
    `to_date` date NOT NULL,
    PRIMARY KEY (`emp_no`,`dept_no`));
    CREATE TABLE `dept_manager` (
    `dept_no` char(4) NOT NULL,
    `emp_no` int(11) NOT NULL,
    `from_date` date NOT NULL,
    `to_date` date NOT NULL,
    PRIMARY KEY (`emp_no`,`dept_no`));
    CREATE TABLE `salaries` (
    `emp_no` int(11) NOT NULL,
    `salary` int(11) NOT NULL,
    `from_date` date NOT NULL,
    `to_date` date NOT NULL,
    PRIMARY KEY (`emp_no`,`from_date`));

    输入描述:

    输出描述:

    emp_nomanager_noemp_salarymanager_salary
    10001 10002 88958 72527
    10009 10010 95409 94409
     
     
     
     
     
     

    答案详解

    select s1.emp_no,s2.emp_no,s1.salary,s2.salary
    from(select p.emp_no,p.dept_no,s.salary
    from dept_emp p inner join salaries s
    on p.emp_no = s.emp_no and p.to_date='9999-01-01' and s.to_date='9999-01-01'
    ) as s1 inner join
    (
    select r.emp_no,r.dept_no,s.salary
    from dept_manager r inner join salaries s
    on r.emp_no = s.emp_no and r.to_date='9999-01-01' and s.to_date='9999-01-01'
    ) as s2
    on s1.dept_no = s2.dept_no where s1.salary >s2.salary
  • 相关阅读:
    懂得拐弯,是人生大智慧!
    人心如落叶
    人生聚散,一切随缘!
    35岁以后你还能干嘛?
    人品好,自带光芒
    有一种心境,叫顺其自然
    304. Range Sum Query 2D
    303. Range Sum Query
    301. Remove Invalid Parentheses
    297. Serialize and Deserialize Binary Tree
  • 原文地址:https://www.cnblogs.com/Bluebells/p/14375550.html
Copyright © 2011-2022 走看看